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mart [117]
3 years ago
12

Each costume needs 46 cm of yellow ribbon the blue ribbon is 3 times larger than the 46 cm there are 64 costumes what is the tot

al length of all the ribbon? I NEED HELP!
Mathematics
2 answers:
fredd [130]3 years ago
7 0

Answer:

The total length ribbon for 64 costumes : 117.76 m

Step-by-step explanation:

bazaltina [42]3 years ago
4 0

Answer:

981.3

Step-by-step explanation:

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4. If DF = 9x - 39, find EF.<br><br> Help I’m so confused!!!!
topjm [15]

Answer:

EF =58

Step-by-step explanation:

from the illustration,

EF =DF - DE

<em>give</em><em>n</em><em> </em><em>that</em><em> </em><em>DF</em><em> </em><em>=</em><em>9</em><em>x</em><em>-</em><em>3</em><em>9</em><em> </em><em>,</em><em> </em><em>DE</em><em> </em><em>=</em><em>4</em><em>7</em><em> </em><em>EF</em><em>=</em><em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em>

<em>sub</em><em>stitute</em><em> </em><em>them</em><em> </em><em>into</em><em> </em><em>the</em><em> </em><em>formu</em><em>la</em><em>,</em>

<em> </em><em> </em>

<em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em><em>=</em><em>9</em><em>x</em><em>-</em><em>3</em><em>9</em><em> </em><em>-</em><em> </em><em>4</em><em>7</em>

<em>sol</em><em>ving</em><em> </em><em>for</em><em> </em><em>x</em>

<em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em><em> </em><em>=</em><em>9</em><em>x</em><em> </em><em>-</em><em>8</em><em>6</em>

<em>grou</em><em>ping</em><em> like</em><em> </em><em>ter</em><em>ms</em>

<em>3</em><em>x</em><em> </em><em>-</em><em> </em><em>9x</em><em> </em><em>=</em><em>-</em><em>8</em><em>6</em><em> </em><em>-</em><em>1</em><em>0</em>

<em>-6x</em><em>=</em><em>-</em><em>9</em><em>6</em>

<em>div</em><em>iding</em><em> </em><em>throu</em><em>gh</em><em> </em><em>by</em><em> </em><em>-</em><em>6</em>

<em>\frac{ - 6x}{ - 6}  =  \frac{ - 96}{ - 6}</em>

<em>x  =  \frac{96}{6}</em>

<em>x = 16</em>

<em>but</em><em> </em><em>EF</em><em>=</em><em>3</em><em>x</em><em>+</em><em>1</em><em>0</em>

substitute x=16 into it to get the EF

EF= 3(16)+10

EF=48+10

EF=58

6 0
3 years ago
Read 2 more answers
About how much difference in average leaf width would you find in two forests whose average annual rainfalls are near 1500 mm bu
goblinko [34]

Answer:

4.80 mm to 2 d.p

Step-by-step explanation:

w = f(r)

f'(r) = (dw/dr) = (0.0218 mm/mm)

So, for a small difference in rainfall of 220 mm, what is the corresponding small difference in width of leaves in the two forests given.

One definition of a derivative or a rate of change is that it is the ratio of very small differences in the dependent variable to very small differences in the independent variable.

Mathematically,

(dw/dr) = (Δw/Δr) for very small Δw and Δr.

0.0218 = (Δw/220)

Δw = 0.0218 × 220 = 4.796 mm = 4.80 mm to 2 d.p

Hope this Helps!!!

5 0
3 years ago
Please help! I will give brainliest (or however you spell it) to whoever gives me the answer!
snow_lady [41]

Answer:

CDF is scaled down by a factor of 1/2 of ABC

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Very buys a basket of mangoes that is priced $14 before tax. ​ ​The sales tax is 6%. ​ ​What is the total price Avery pays for t
igor_vitrenko [27]

Answer:

Avery needs to pay $14.84

Step-by-step explanation:

When there's a tax we need to sum the original value of the product with the tax's value. To find the amount of money Avery needs to pay in taxes we can apply a rule of three as shown below:

\frac{14}{x} = \frac{100}{6} \frac{\%}{\%}

Where "x" is the tax value, and $14 represents 100%, since it's the value used to calculate the tax. We have:

x = \frac{14*6}{100}\\x = \frac{84}{100}\\x = 0.84

The value to be paid is the product value plus the tax, therefore:

\text{paid} = 14 + 0.84 = 14.84

Avery needs to pay $14.84

6 0
3 years ago
Find the measure of the arc.<br><br> 146°E<br><br> mFD =
Verizon [17]

Answer:

arc FD = 236°

Step-by-step explanation:

The measure of the arc is equal to the measure of the central angle it subtends, thus

arc FD = arc FE + arc ED = 146° + 90° = 236°

4 0
3 years ago
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