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Sati [7]
3 years ago
10

Find the capacity of the tanks with the following internal dimensions. Express the capacity in cubic meters and liters for each

tank.​

Mathematics
1 answer:
Vladimir [108]3 years ago
3 0

Step-by-step explanation:

i) Capacity(Volume) = length x breadth x depth

= 3.2 x 2.9 x 1.5

= 13.92 m³

In litres, 13.92 x 1000 = 139,20 litres

ii) Capacity(Volume) = length x breadth x depth

= 2.5 x 1.6 x 1.3

= 5.2 m³

In litres, 5.2 x 1000 = 5200 litres

iii) Capacity(Volume) = length x breadth x depth

= 7.3 x 3.6 x 1.4

= 36.792 m³

In litres, 36.792 x 1000 = 36,792 litres

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An artist printed 1026 greeting cards and plans to package them for distribution. How many can be put into each box so theres no
OleMash [197]

Answer:

B

Step-by-step explanation:

18 is the only number given that can be divided without having a remainder or decimal.

1026 ÷ 18 = 57

4 0
2 years ago
The parabola y=x^2 is shifted up by 8 units
dangina [55]

Answer:

It becomes y = x^2 + 8.

Step-by-step explanation:

The equation of the new parabola is y = x^2 + 8.

6 0
3 years ago
(08.05 LC)<br><br> Which two-dimensional shape can be rotated about the y-axis to create a cone?
Illusion [34]

Any right triangle can.

4 0
3 years ago
Read 2 more answers
Gracie is shipping a cube shaped box. It measures 14in x 14in x 14in. What is the surface area of the box?
DanielleElmas [232]
14× 14 = 196 area of 1 of the squares. on a cube there are 6 squares so multiply 196 by 6

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8 0
3 years ago
Please help me out with this!!<br> BRAINLIEST AVAILABLE!!
lapo4ka [179]

Answer:

xy = 1

k = 79

Step-by-step explanation:

Question One

The first and third frames look to me to be the same. I'll treat them that way.

y = x^2                        Equate y = x^2 to the result of 2y + 6 = 2x + 6

2y + 6 = 2(x + 3)         Remove the brackets

2y + 6 = 2x + 6           Subtract 6 from both sides

2y = 2x                       Divide by 2

y = x

Now solve these two equations.

so x^2 = x                  

x > 0

1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is

x(x) = x                           Divide both sides by x            

x = 1                            

y = x^2                           Put x = 1 into x^2

y = 1^2                           Solve

y = 1                      

The second solution is

(1,1)

xy = 1*1

xy = 1

Answer: A

Question Two

square root(k + 2) - x = 0

Subtract x from both sides

sqrt(k + 2) = x                Square both sides

k + 2 = x^2                    Let x = 9

k + 2 = 9^2                    Square 9

k + 2 = 81

k = 81 - 2

k = 79

4 0
3 years ago
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