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lina2011 [118]
2 years ago
11

2) If Michael invests $2000 in the bank at a rate of 5.5% for 6 years how much

Mathematics
1 answer:
Bad White [126]2 years ago
3 0

Answer:

nnn

Step-by-step explanation:

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Greg purchased supplies for a party. He had a coupon good for 30% off. He purchased a helium tank rental with an original price
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The correct answer is (A) cake
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Figure A was drawn first and figure B was drawn second. What is the scale factor?
kakasveta [241]
The answer is A because you are multiplying it by 2
3 0
2 years ago
Which of the following approximates the ratio of 6 to 198? Select all that apply. 3 out of 10 3 × 10−2 3 out of 1,000 3 × 102 3
Jobisdone [24]

this is approximately 6 to 200

divide both by 2

3 to 100

3 to 10^2

3 out of 100

5 0
3 years ago
Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)
Fantom [35]

Answer:

Given: \sin(x) = (4/5).

Assuming that 0 < x < 90^{\circ}, \cos(x) = (3/5) while \tan(x) = (4/3).

Step-by-step explanation:

By the Pythagorean identity \sin^{2}(x) + \cos^{2}(x) = 1.

Assuming that 0 < x < 90^{\circ}, 0 < \cos(x) < 1.

Rearrange the Pythagorean identity to find an expression for \cos(x).

\cos^{2}(x) = 1 - \sin^{2}(x).

Given that 0 < \cos(x) < 1:

\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}.

Hence, \tan(x) would be:

\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}.

7 0
2 years ago
Simplify this expression
pishuonlain [190]

Answer:

After simplifying, the exponent of x is 33 and the exponent of y is 0

Step-by-step explanation:

For us to simplify, we bring the x base together and the y base together

Recall from the law of indices;

x^a/x^b = x^(a-b)

and x^a * x^b = x^(a + b)

We shall be applying these here

Let us bring the x terms together

we have these as;

x^8/x^14 * 1/x^-39 = x^( 8 - 14 -(-39))

= x^(8 + 39-14) = x^33

for y, we have it that;

y^-26/y^-5 * 1/y^-21

= y^(-26 -(-5) - (-21)

= y^-26 + 5 + 21 = y^0

8 0
3 years ago
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