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3 years ago

Factor the trinomial by grouping. 6x^2 - 7x-20

Mathematics

1 answer:

mezya [45]3 years ago

4 0

Answer:

(3x+4)(2x-5)

Step-by-step explanation:

You have 6x^2 - 7x-20, you add and take 8x so now you have

6x^2 - 7x +8x -8x -20 now you take 6x^2 and the +8x and factorize

6x^2 +8x = 2x( 3x +4 )

and you have -7x -8x-20 = -15x -20 factorize

-5(3x +4 ) add all up.

2x(3x +4) -5(3x +4) and you have

(3x+4)(2x-5)

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2 years ago

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3 years ago

Read 2 more answers

Expand a logarithmic expression

ivanzaharov [21]

The logarithmic expression is

$log (\sqrt{z^5}/(x^3y))$

To expand the expression we have to use some properties of logarithm.

We know that $log(m/n) = log (m) - log(n)$

By using this property we can write,

$log(\sqrt{z^5}) - log(x^3y)$

Square root means to the power 1/2, so for $\sqrt{z^5}$ , we can write $z^(5/2)$ .

$log(z^(5/2)) - log(x^3y)$

Now we have to use another property of logarithm.

We know that, $log(mn) = log(m) + log(n)$

So we will use this property to $log(x^3y)$

$log(z^(5/2)) - log(x^3y)$

$log(z^(5/2)) - (log(x^3) + log(y))$

$log(z^(5/2)) - log(x^3) - log(y)$

Now we have to use another property of logarithm.

We know that, $log(a^m) = m log(a)$

By using this property we can write,

$(5/2)log(z) - 3log(x) - log(y)$

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3 years ago

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Which set of numbers CANNOT represent the lengths of the sides of a triangle?

posledela

Answer:

Step-by-step explanation:

The general rule is that any 2 must exceed the third in order for a triangle to form. If any one is an exception, it won't work.

A will form a triangle. Any 2 exceeds the third.

B also forms a triangle. Same rule.

C does not work. 7 + 11 = 18 which is the value of the third leg.

D words Any two exceeds the 3rd.

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3 years ago