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2 years ago

Please help me!!!!!!!!!!!!!!

Mathematics

1 answer:

9966 [12]2 years ago

8 0

Answer:

See below

Step-by-step explanation:

I can't draw it for you so here are the points. Draw your triangle with them.

From the original triangle, to rotate 180 degrees around the origin, just imagine your are flipping your computer screen upside down which is 180 degrees. To get the coordinates for the points, just make each x and y value the opposite of what the origin is.

Original points ( 2, 1 ) ( 5, -2 ) ( 3, -4 )

Rotated points ( -2, -1 ) ( -5, 2 ) ( -3, 4 )

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What is the volume? 7 yd 10 yd 6 yd

Tju [1.3M]

Answer:

210 yd³

Step-by-step explanation:

Volume of a triangular prism

= the area of a triangular base × the height

The area of the base

= (10×7)÷2

= 35 yd²

The volume of the prism

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3 0

3 years ago

Evaluate the expression if x = 3 and y = 6. 4x + 3y

mylen [45]

Here, Just substitute their values,
4x + 3y
= 4(3) + 3(6)
= 12 + 18
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In short, Your Answer would be 30

Hope this helps!

3 0

2 years ago

Read 2 more answers

Find cos(2*ABC) 100POINTS

juin [17]

Answer:

$-\dfrac{7}{25}$

Step-by-step explanation:

Trigonometric Identities

$\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B$

Trigonometric ratios

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos(\angle ABC)=\dfrac{3}{5}$

$\sin(\angle ABC)=\dfrac{4}{5}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}$