the sum of three numbers is 131. the third number is 4 times the first. the second number is 5 more than the first. what are the
numbers
1 answer:
Step-by-step explanation:
let the numbers are:
a, b, and c
the equation would be:
a+b+c = 131
c = 4a
b = a+5
=>
a + a+5 +4a = 131
6a +5 = 131
6a = 131-5
6a = 126
a= 126/6
a = 21
b = a+5 = 21+5
b = 26
c = 4a = 4(21)
c = 84
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