The line segment HI has length 3<em>x</em> - 5, and IJ has length <em>x</em> - 1.
We're told that HJ has length 7<em>x</em> - 27.
The segment HJ is made up by connecting the segments HI and IJ, so the length of HJ is equal to the sum of the lengths of HI and IJ.
This means we have
7<em>x</em> - 27 = (3<em>x</em> - 5) + (<em>x</em> - 1)
Solve for <em>x</em> :
7<em>x</em> - 27 = (3<em>x</em> + <em>x</em>) + (-5 - 1)
7<em>x</em> - 27 = 4<em>x</em> - 6
7<em>x</em> - 4<em>x</em> = 27 - 6
3<em>x</em> = 21
<em>x</em> = 21/3
<em>x</em> = 7
Answer:
75 ≤ length < 85
Step-by-step explanation:
You know a number 5 or greater will round up to the next higher number in the number place to its left. Similarly, numbers less than 5 round down (get replaced by zero).
This means that 75 will round up to 80. and 84.9999... will round down to 80.
a) The lower bound on length is 75. The length must be at least 75.
b) The upper bound on length is 85. The length must be less than 85.
Answer:
4,000 enroll
Step-by-step explanation:
If 20,000 students apply and the university only accepts 40%, the university accepted 8,000 students.
How many actually enrolled?
Of those accepted students (8,000), 50% enroll.
8,000 / 2 OR 8,000 x 0.50 = 4,000 students actually enroll.
