If 8a+2b+7c=4 what is -7c–
1 answer:
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Answer: The distance is sqrt(40).
Step-by-step explanation:
Let's use the Pythagorean Theorem (a^2 + b^2 = c^2)
(Look at the image I attached)
Let's set a = 2 and b = 6. The mystery side is c, which is opposite to the right angle that is formed when you draw perpendicular lines from each of the points.
(2)^2 + (6)^2 = c^2 <--- First, we need to simplify
4 + 36 = c^2
40 = c^2 <--- Now, we need to take the square root of both sides.
c = sqrt(40)
So, the distance between (5, -4) and (-1, -2) is sqrt(40). I recommend looking at some videos on Khan Academy if you need more help! Let me know if you want me to attach a link that you can visit.
I hate rounding.
Let's call the diagonal x. It's the hypotenuse of the right triangle whose legs are the rectangle sides.
According to the problem we have a length x-4 and a width x-5 and an area
82 = (x-4)(x-5)
82 = x^2 - 9x + 20
0 = x^2 - 9x - 62
That one doesn't seem to factor so we go to the quadratic formula
Only the positive value makes any sense for this problem, so we conclude
That's the exact answer. Did I mention I hate rounding? That's about
x = 13.6 meters
Answer: 13.6
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It's not clear to me this problem is consistent. By the Pythagorean Theorem the diagonal satisfies
which works out to
That's not consistent with the first answer; this problem really has no solution. Tell your teacher to get better material.