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Lelechka [254]
3 years ago
6

1.5 Code Practice: Question 1

Computers and Technology
1 answer:
Jobisdone [24]3 years ago
6 0
What’s the question?
Always remember to add any reasonable information for someone to help or answer!!

Have a good rest of your day.
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An abstraction is a simplified representation of something that is more complex. Decimal numbers were a useful abstraction in th
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What was the content of the lesson? It is hard to answer a question we need context on.

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Write a program that helps a young student learn to make change. Use the random number generator to generate change amounts betw
erastovalidia [21]

Answer:

#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

 

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

 

int quarters = coins/25;

 

coins = coins%25;

 

int dimes = coins/10;

 

coins = coins%10;

 

int nickles = coins/5;

coins = coins%5;

 

int pennies = coins/1;

 

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

 

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

 

}

 

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

 

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

 

int quarters = coins/25;

 

coins = coins%25;

 

int dimes = coins/10;

 

coins = coins%10;

 

int nickles = coins/5;

coins = coins%5;

 

int pennies = coins/1;

 

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

 

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

 

}

 

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}

Explanation:

  • Use the built-in rand function to generate a random coin.
  • Get all the required values for quarters, dimes, nickles and pennies and store them in variables.
  • Check if the coins give a value of temp, then answer is correct and the values of user will be added.
  • Optimum solution is displayed  If it does not matches with the optimum solution. Display that the answer is wrong along with solution.
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A film producer is having difficulty with distribution. After major and minor theaters show no interest in the film, what would
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Answer:

pursue internet distribution

Explanation:

4 0
3 years ago
Statement: There are two files. One file, "badIP_list.txt" has a listing of known bad IP addresses. These addresses were extract
lapo4ka [179]

Answer:

See explaination

Explanation:

SOURCE CODE IN PYTHON:

inp=open('badIP_list.txt', 'r') #opening file for input

badIPs=[i.rstrip('\n') for i in inp.readlines()] #reading bad IPs

inp.close() #closing file

inp=open('server_logs.txt', 'r') #opening file for input

IPs=[i.rstrip('\n') for i in inp.readlines()] #reading all IPs from log

inp.close() #closing file

uniqueBadIPs=[] #to store unique bad IPs

countBadIPs=0 #to store count of bad IPs

countIPs=0 #to store count of all IPs

for IP in IPs: #iterating through the log of IPs

if IP in badIPs: #checking if IP is bad

countBadIPs+=1

if IP not in uniqueBadIPs: #checking if bad IP is unique

uniqueBadIPs.append(IP)

countIPs+=1

out=open('filter_list.txt', 'w') #opening file for output

out.write('_________________________________________________________\n')

out.write('Date : 26/07/2018\nName : Last, First\nMajor: CS\n\n')

out.write('Server logs contained these known bad IP addresses:\n')

for IP in uniqueBadIPs: #output the unique bad IPs

out.write(IP+'\n')

out.write('\n')

out.write('Total unique known bad IP\'s detected:\n'+str(len(uniqueBadIPs))+'\n\n')

out.write('Percentage of bad IP addresses in server logs:\n{:.2f}%\n'.format(countBadIPs*100/countIPs))

out.write('_________________________________________________________')

out.close() #closing file

5 0
4 years ago
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