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2 years ago

Will mark brainliest, 100 pts

Mathematics

2 answers:

Semmy [17]2 years ago

8 0

Answer:

Step-by-step explanation:

Shalnov [3]2 years ago

4 0

A. Gross pay = $9.50/hr * 40hrs = $380
B. Income tax = 10% paycheck = $38
C. Take home pay = $380 - $38 = $342

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2x-5/5 +x-2=3(x+5). Find the value of x?

deff fn [24]

Answer:

Step-by-step explanation:

$\frac{2x - 5}{5} + x - 2 = 3(x + 5)$

$\frac{2x - 5}{5} + x - 2 = 3x + 15$

$\frac{2x - 5}{5} = 2x + 17$

$2x - 5 = 10x + 85$

$-8x = 90$

$x = \frac{-45}{4}$

5 0

3 years ago

Suppose that a market research firm is hired to estimate the percent of adults living in a large city who have cell phones. 500

Alborosie

Answer:

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 500, \pi = \frac{421}{500} = 0.842$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 - 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.81$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 + 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.874$

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

6 0

3 years ago

1. In what country did the government debate the merit of teaching students quadratics? 2. What modern technology would not be p

Alexxandr [17]

I would say number 2 but dont take my word for it

6 0

3 years ago

Use the "at least once" rule to find the probability of getting at least one 2 in four rolls of a single fair die.

Alexandra [31]

Answer:

Probability of getting at least one 2 equals 0.5177

Step-by-step explanation:

The probability of at least one success is

$P=1-(1-p)^{n}$

where,

'p' is probability of success of 1 trail

'n' is number of events

We have probability of getting 2 is 1/6 thus 'p' = 1/6

Applying values we get

$P=1-(1-\frac{1}{6})^{4}\\\\P= 0.51177$

8 0

3 years ago

A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hit the ground. a.Find

Lyrx [107]

A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>

4 0

3 years ago