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Dahasolnce [82]
3 years ago
10

1. In what country did the government debate the merit of teaching students quadratics? 2. What modern technology would not be p

ossible without quadratics? (hint: I have one at my house.) 3. What great ideas did the Babylonians come up with? 4. Why did the Babylonians need to solve quadratic equations?
Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0
I would say number 2 but dont take my word for it 
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When we reject the null and the null is true, we have a made a _________ __________.
nydimaria [60]

When we reject the null and the null is true, we have a made a type I error

The null hypothesis in statistics states that there is no difference between groups or no relationship between variables. It is one of two mutually exclusive hypotheses about a population in a hypothesis test.

null hypothesis is denoted as H₀

Reject the null hypothesis when the p-value is less than or equal to your significance level. Your sample data favor the alternative hypothesis, which suggests that the effect exists in the population. When you can reject the null hypothesis, your results are statistically significant.

when the p-value is greater than your significance level, you fail to reject the null hypothesis.

Sometimes , we reject our null hypothesis even when its true

there we made a type I error in hypothesis

To know more about null hypothesis here

brainly.com/question/19263925

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3 0
1 year ago
The function h(x) = 1/2 (x+3)2 +2. How is the graph of the h(x) translated from the parent graph of a quadratic function, F(x) =
Natali5045456 [20]
For this case, the parent function is given by:
 F (x) = x ^ 2

 We apply the following function transformation:
 Vertical compressions:
 To graph y = a * f (x)
 If 0 <a <1, the graph of y = f (x) is compressed vertically by a factor a. (Shrinks)
 We have then:
 y = (1/2) * x ^ 2&#10;
 Horizontal translations:
 Suppose that h> 0
 To graph y = f (x + h), move the graph of h units to the left.
 We have then:
 y = (1/2) * (x + 3) ^ 2&#10;
 Vertical translations:
 Suppose that k> 0
 To graph y = f (x) + k, move the graph of k units up.
 We have then:
 h (x) = (1/2) * (x + 3) ^ 2 + 2&#10;
 Answer:
 
Vertical compression by factor of 1/2. Horizontal displacement 3 units to the left. Vertical displacement 2 units up.
3 0
2 years ago
Why is 3÷0.5 is 6, why is it?​
Alekssandra [29.7K]

Answer:

Step-by-step explanation:

A quick way to divide by 0.5 or ½ is to double the number (or multiply number by 2). The reason for this is that two halves go into a whole.

3 0
2 years ago
Required information Skip to question NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to re
pogonyaev

The result for the given 14 length bit string is-

(a) The bit strings of length 14 which have exactly three 0s is 2184.

(b) The bit strings of length 14 which have same number of 0s as 1s is 17297280.

(c) The bit strings of length 14 which have at least three 1s is 4472832.

<h3>What is a bit strings?</h3>

A bit-string would be a binary digit sequence (bits). The size of the value is the amount of bits contained in the sequence.

A null string is a bit-string with no length.

The concept used here is permutation;

ⁿPₓ = n!/(n-x)!

Where, n is the total samples.

x is the selected samples.

(a) Because there are exactly three 0s, its other digits have always been one, hence the total of permutations is equal to;

n = 14 and x = 3 digits.

¹⁴P₃ = 14!/(14-3)!

¹⁴P₃ = 2184.

Thus, the bit strings of length 14 which have exactly three 0s is 2184.

(b) Because it is a bit string with 14 digits and it can only have digits 0 or 1, we must choose 7 0s and the remaining 7 1s, hence the number possible permutations is equal to;

n = 14 and x = 7 digits.

¹⁴P₇ = 14!/(14-7)!

¹⁴P₇ = 17297280.

Thus, the bit strings of length 14 which have same number of 0s as 1s is 17297280.

(c) The answer is identical to problem a, but the rest of a digits could be either 0 or 1, hence it must be doubled by 2¹¹ because there are 11 digits, each of which can be one of two options;

= 2184×2¹¹

= 4472832

Thus, he bit strings of length 14 which have at least three 1s is 4472832.

To know more about permutation, here

brainly.com/question/12468032

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The correct question is-

How many bit strings of length 14 have:

(a) Exactly three 0s?

(b) The same number of 0s as 1s?

(d) At least three 1s?

3 0
1 year ago
PLEASE HELP! Answer quickly for points!! There are 5 times as many tomato plants as there are cucumber plants. The number of pep
miskamm [114]
Let x= cucumber plants
5x= tomato plants
6x+7= pepper plants
peppers = 19 
therefore
6x+7=19
subtract 7 from both sides
6x= 12
 divide both sides by 6
x=2
replace the x with 2

2= cucumber plants
10= tomato plants

hope this helps
3 0
3 years ago
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