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Dahasolnce [82]
3 years ago
10

1. In what country did the government debate the merit of teaching students quadratics? 2. What modern technology would not be p

ossible without quadratics? (hint: I have one at my house.) 3. What great ideas did the Babylonians come up with? 4. Why did the Babylonians need to solve quadratic equations?
Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0
I would say number 2 but dont take my word for it 
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consider the equation is Y equals 1/square root of x and y=x-2. approximate solution of the system equations
emmasim [6.3K]

Answer:

x=1 and x=4

Step-by-step explanation:

We have the following system of equations:

y=\sqrt{x} and y=x-2

To solve the problem, we need to equal the two equations:

x-2=\sqrt{x} ⇒ (x-2)^{2} =x ⇒ x^{2} -4x + 4 = x  

⇒ x^{2} -5x + 4 = 0  

So you need to find two numbers that added equal to 5 and multiplied equal to 4. These two numbers are x=-1 and x=-4.

Then, the factorized form of the polynomial is: (x-1)(x-4).

The, the solution to the system of equations is: x=1 and x=4.

5 0
3 years ago
Solve the following systems by substitution
Paladinen [302]

Answer:

The answer to your question is below

Step-by-step explanation:

Question 1

                x = 5                       Equation l

                2x + y = 10              Equation ll

- Substitute Equation l in equation ll

               2(5) + y = 10

                y = 10 - 10

                y = 0

- Solution  (5, 0)

Question 2

                 x + 16y = 20          Equation l

                 x = 4y                    Equation ll

Substitute equation ll in equation l

                4y + 16y = 20

                        20y = 20

                           y = 20/20

                           y = 1

-Find x

                x = 4(1)

                x = 4

-Solution

                (4, 1)

Question 3

                   2x + 8y = 20            Equation l

                     x = 2                       Equation ll

-Substitute equation ll in equation l

                   2(2) + 8y = 20

                      4 + 8y = 20

                            8y = 20 - 4

                            8y = 16

                              y = 16/8

                              y = 2

- Solution

                   (2, 2)              

8 0
3 years ago
Why is there so many old men asking me if they can su ck my P U $sy????? Im 14 like dam look
mash [69]

Answer:

guys just be like dat

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve the simultaneous equations<br> y-2x=6<br> y+2x=0
elena-14-01-66 [18.8K]
Y-2x=6 => y=6+2x
Y+2x=0
(6+2x) + 2x = 0
6 + 4x = 0
4x= 6
X=6/4
X= 3/2
Y=6+2x
Y=6+2. 3/2
Y= 6 + 3
Y=9
Check: y-2x=6
9-2. 3/2 = 6
9 - 3 = 6
5 0
3 years ago
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
3 years ago
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