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Rashid [163]
2 years ago
13

A 5 inchx 7inch photograph is placed inside a picture frame. Both the length and the width of the frame are 2x inches larger tha

n the width and length of the photograph. Which expression represents the perimeter of the frame?
Mathematics
1 answer:
dolphi86 [110]2 years ago
6 0

Answer:24+4x

Step-by-step explanation:

a=5. PHOTO

b=7. PHOTO

a1=5+x. FRAME

b1=7+x. FRAME

Pf=2*(a1+b1)

Pf=2*(5+x+7+x)

Pf=2*(12+2x)

---------Pf=24+4x. - - - - - - PERIMETER OF FRAME

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Using the Law of Diminishing Marginal Utility, Jane would not be better off buying one more fry, since the marginal utility she obtains from the fries are lower when compared to the chicken sandwich; therefore, she would be better off ordering another chicken sandwich

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AVprozaik [17]

Answer: 12.6 m

Step-by-step explanation:

Use the pythagorean theorem, we get that the height, or x, is

sqrt(22x22-18x18) = sqrt(484-324) = sqrt(160) = 4sqrt(10) = 12.6 m

4 0
2 years ago
Read 2 more answers
72
Zigmanuir [339]

Answer:

Ai. Arithmetic sequence

Aii. Tn = 5 + 7n

Bi. Geometric

Bii. Tn = 8 × 2ⁿ¯¹

Step-by-step explanation:

To successfully answer the questions given above, note the following:

1. If the sequence is Arithmetic, then:

2nd – 1st = 3rd – 2nd = common difference (d)

2. If the sequence is geometric, then,

2nd / 1st = 3rd / 2nd = common ratio (r)

3. A sequence can not be arithmetic geometric at the same time.

4. The nth term of arithmetic sequence is:

Tn = a + (n – 1)d

5. The nth term of geometric sequence is:

Tn = arⁿ¯¹

A. Sequence => 12, 19, 26

i. Determination of the type of sequence.

We'll begin by calculating the common difference

1st term = 12

2nd term = 19

3rd term = 26

Common difference (d) = 2nd – 1st

d = 19 – 12 = 7

OR

d = 3rd – 2nd

d = 26 – 19 = 7

Since a common difference exist in the sequence, the sequence is arithmetic sequence.

ii. Determination of the nth term.

Common difference (d) = 7

1st term (a) = 12

nth term (Tn) =?

Tn = a + (n – 1)d

Tn = 12 + (n – 1)7

Tn = 12 + 7n – 7

Tn = 5 + 7n

B. Sequence => 8, 16, 32

Bi. Determination of the type of sequence.

Let us begin by calculating the common ratio.

1st term = 8

2nd term = 16

3rd term = 32

Common ratio (r) = 2nd / 1st

r = 16 / 8

r = 2

OR

r = 3rd / 2nd

r = 32 / 16

r = 2

Since a common ratio exist in the sequence, the sequence is geometric.

Bii. Determination of the nth term.

Common ratio(r) = 2

1st term (a) = 8

nth term =?

Tn = arⁿ¯¹

Tn = 8 × 2ⁿ¯¹

8 0
2 years ago
Simplify the given expression, using only positive exponents. then complete the statements that follow. [ (x2y3)−1 (x−2y2z)2 ] 2
PolarNik [594]
[(x**-2) y**2 .z)**2]**2        (x**-8)(y**8)(z**4)
----------------------- =        ----------------------------- 
[x**2 . y**3]**2                   (x**4) (y**6)


     (y**8)(z**4)            (y**2)*(z**4)
    --------------------- = -------------
    (x**12) (y**6)             (x**12)

7 0
3 years ago
Read 2 more answers
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