Step-by-step explanation:
Todd fills 30 paper cups with ketchup and Yuki fills 27 paper cups with ketchup.
Each paper cup holds 1 ounce
Todd = 30 * 1 = 30 ounces
Yuki = 27 * 1 = 27 ounces
Total ounces = 30 + 27
Later, Todd and Yuki learn that two other company employees completed exactly the same task.
Total ounces = 2 (30 + 27)
^ 3 sqrt 750 + ^ 3 sqrt 2058 - ^ 3 sqrt 48
Rewriting the expression we have
^ 3 sqrt (6 * x ^ 3) + ^ 3 sqrt (6 * y ^ 3) - ^ 3 sqrt (6 * z ^ 3)
That is, we have the following equations:
6 * x ^ 3 = 750
6 * y ^ 3 = 2058
6 * z ^ 3 = 48
Clearing x, y and z we have:
x = 5
y = 7
z = 2
Then, rewriting the expression
x (^ 3 sqrt (6)) + y (^ 3 sqrt (6)) - z (^ 3 sqrt (6))
Substituting the values
5 (^ 3 sqrt (6)) + 7 (^ 3 sqrt (6 *)) - 2 (^ 3 sqrt (6))
10 (^ 3 sqrt (6))
answer
the simple form of the expression is
D) 10 ^ 3 sqrt 6
So 72 pencils and 24 calculators
so greates number of identical calculators
this means
what is the biggest number that we can divide 72 and 24 by and get a whole number
this is called the GCM or greatest common multipule
to find the GCM, you factor 72 and group the like ones
72=2 times 2 times 2 times 3 times 3
24=2 times 2 times 2 times 3
so the common group is 2 times 2 times 2 times 3 or 24
so the greates number of packs is 24
so pencils
72 divided by 24=72/24=3
3 pencils per pack
24 divided by 24=24/24=1
1 calulator per pack
answer is 3 pencils and 1 calculator per pack
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
A) A=500(1+0.015)^t
b)800=500(1.015)^t
800/500=1.015^t
t=log(800/500)/log(1.015)
t=31.6 years
