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Katena32 [7]
2 years ago
14

. 1 Find f for the function f. f(x) = 3x² + 3, x > 0 And find the domain

Mathematics
1 answer:
konstantin123 [22]2 years ago
8 0

Answer:

y = \sqrt{\frac{x-3}{3} }

Domain = [3, infinity)

Step-by-step explanation:

x = 3y^2 + 3

3y^2 = x - 3

y^2 = (x-3)/3

y = \sqrt{\frac{x-3}{3} }

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Anita needs to buy 7 1/2 feet of packaging tape. There are 1 1/2 feet of tape on each roll. How
valkas [14]

Answer:

5

Step-by-step explanation:

you don't have to but i convert 7 1/2 and 1 1/2 into 7.5 and 1.5 to make it easier than you divide.

8 0
2 years ago
List all the factors of 84​
Ray Of Light [21]

✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽

Factors of 84 : 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42 and 84.

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3 0
3 years ago
Pls hurryyyyyy math test
Bezzdna [24]

Answer:

45 degrees

Step-by-step explanation:

4 0
2 years ago
Performance Matters
spayn [35]

Answer:

the 1st, 2nd and 6th statements are true.

and probably the 3rd statement is true.

I am not sure about the 3rd statement, as I cannot read the original in your screenshot, and your transcribed description is probably not correct and contains typos.

but all you need is in the explanation below to decide, if the actual 3rd statement is true or not.

if "58 + 79 = 1268" actually means "5s + 7g = 1268" then it is true. otherwise it is false.

Step-by-step explanation:

g = number of general tickets sold

s = number of student tickets sold

so, in total

g + s = 234

tickets were sold.

and the revenue was

7g + 5s = $1,268

out of these 2 basic equating we get

g = 234 - s

and then

7(234 - s) + 5s = 1,268

1,638 - 7s + 5s = 1,268

-2s = -370

s = 185

g = 234 - s = 234 - 185 = 49

so, we know

185 student tickets were sold for 5×185 = $925

49 general tickets were sold for 7×49 = $343

7 0
2 years ago
9/4,3/8,1/3 what is the least common denominator plz show work
Alexus [3.1K]
4, 8, and 3 must all go into the number. find the LCM(4,8) is 8. the LCM(8,3) is 24. that's your answer, 24
7 0
3 years ago
Read 2 more answers
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