3 years ago

Which is the area between the x-axis and y=x from x=1 to x=6

1 answer:

6 0

Answer:

I am going to answer using calculus. Let me know if you instead were looking for an algebraic method. Take the definite integral from 3 to 6 of xdx. [x^2/2]3 to 6= 18-(9/2)= (36-9)/2= 27/2. The area is 27/2

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guajiro [1.7K]

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Elanso [62]

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3 years ago

Read 2 more answers

NEEED HELP ASAP PLEASE

garik1379 [7]

Step-by-step explanation:

$( {m}^{15} )( {m}^{3} ) ^ {- 4} \\ = ( {m}^{15} )( {m}^{3 \times - 4} ) \\ = ( {m}^{15} )( {m}^{ - 12} ) \\ = {m}^{15 + ( - 12)} \\ = {m}^{15 - 12} \\ = {m}^{3} \\ {m}^{x} = {m}^{3} \\ x = 3$

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