Answer:
https://www.digitalunite.com/technology-guides/computer-basics/using-computer/how-use-computer-keyboard
Explanation:
the link at the top should explain it all! :)
Answer:
#include <iostream>
#include <map>
using namespace std;
int main()
{
map<int, int> numbers;
cout << "Enter numbers, 0 to finish" << endl;
int number;
while (true) {
cin >> number;
if (number == 0) break;
numbers[number]++;
}
for (pair<int, int> element : numbers) {
std::cout << element.first << ": occurs " << element.second << " times" << std::endl;
}
}
Explanation:
One trick used here is not to keep track of the numbers themselves (since that is not a requirement), but start counting their occurrances right away. An STL map< > is a more suitable construct than a vector< >.
<span>In certain cases, when the Swen executable is removed or renamed by an anti virus program without stopping to fix the registry, it then will become impossible to run any executable files on the machine. This happens because windows will be unable to find the file that is associated with any executables on it's hard drive.</span>
Answer:
This is a multicolinearity problem and the student should determine the variable(s) that cause(s) the problem and remove it.
Explanation:
This information means that there exists a linear combination between the independent variables. The problem might have developed due to multicolinearity producing almost perfectly linearly dependent columns.
This could also be as a results of single matrix created when the student use an incorrect indicator variables and included an additional indicator column which created linearly dependent columns.
Answer:
a = 6, b = 0
Explanation:
The loop ran 3 times before b == 0. "while ((b != 0)" is essentially saying: 'While b is not equal to 0, do what's in my loop'. Same general thing with "&& ((a / b) >= 0)". The "&&" is specifying that there should be another loop condition, while the rest states: 'as long as a ÷ b is greater than 0, do what's in my loop'. If both of these conditions are met, the loop will run, It will continue this until the conditions are not met. Hope that helped! :)
