a.NH₃+HCl⇒NH₄Cl
b.volume HCl=150 ml
c. pH=4.82
<h3>Further explanation</h3>
Reaction
NH₃+HCl⇒NH₄Cl
The equivalence point⇒mol NH₃=HCl
Titration formula :
M₁V₁n₁=M₂V₂n₂(n=acid base valence, NH₃=HCl=1)
mol NH₃
mol HCl=75 mlmol
Volume total :
mol NH₄Cl=mol NH₃=75 mlmol=0.075 mol
Dissociation of NH₄Cl at water to find [H₃O⁺]
ICE at equilibrium :
0.41-x x x
Ka(Kw:Kb)= 10⁻¹⁴ : 1.8.10⁻⁵=5.6.10⁻¹⁰
[H₃O⁺]=x :
pH=-log[H₃O⁺]
We assume that the given gas, NO2, is an ideal gas such that we will be able to use the equation,
n/V = P/RT
where n is the number of moles, V is volume, P is pressure, R is gas constant, and T is temperature in kelvin. Substituting the known values,
n/V = (1 atm) / (37 + 273)(0.0821 L.atm/mol.K)
n/V = 0.039 mol/L
Converting this to density by multiplying the value with the molar mass,
density = (0.039 mol/L) x (46 g/mol) = 1.8 g/L
Answer:
Energy is halved.
Explanation:
Energy and Frequency are directly proportional. If frequency decreases, energy increases. If frequency increases, energy increases. If frequency is halved, energy is also halved.
The answer is (3) HClO3. The percent composition mass of chlorine is equals to the mass of one Cl atom /gram-formula mass of the compound. So after calculation, we can get the right answer.
miscible cause the clear blue liquid is a homogeneous mixture
