When water is heated to transform from a liquid to a gas
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Answer:
The dots were not properly located and arrows are not used in Lewis structures
Explanation:
If we intend to write a Lewis structure for a compound, that lewis structure must consist of only dots. These dots actually show the valence electrons on the outermost shell of the molecule.
We do not involve arrows when writing dot electron structures for compounds. The valence electrons of magnesium ought not to be written together because they are not a lone pair, rather they are two unpaired electrons. The use of an arrow suggests a coordinate covalent bond which is not the case here.
The correct lewis structure for MgCl2 is shown in the image attached to this answer.
Taking into account the reaction stoichiometry, 10.93 grams of CO₂ are formed when 8.50 g of methane react with 15.9 g of O₂.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
CH₄ + 2 O₂ → CO₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- CH₄: 1 mole
- O₂: 2 moles
- CO₂: 1 mole
- H₂O: 2 moles
The molar mass of the compounds is:
- CH₄: 16 g/mole
- O₂: 32 g/mole
- CO₂: 44 g/mole
- H₂O: 18 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- CH₄: 1 mole ×16 g/mole= 16 grams
- O₂: 2 moles ×32 g/mole= 64 grams
- CO₂: 1 mole ×44 g/mole= 44 grams
- H₂O: 2 moles ×18 g/mole=36 grams
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
<h3>Limiting reagent in this case</h3>To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 16 grams of CH₄ reacts with 64 grams of O₂, 8.50 grams of CH₄ reacts with how much mass of O₂?
mass of O₂= 34 grams
But 34 grams of O₂ are not available, 15.9 grams are available. Since you have less mass than you need to react with 8.50 grams of CH₄, O₂ will be the limiting reagent.
<h3>Mass of CO₂ formed</h3>The following rule of three can be applied: if by reaction stoichiometry 64 grams of O₂ form 44 grams of CO₂, 15.9 grams of O₂ form how much mass of CO₂?
<u><em>mass of CO₂= 10.93 grams</em></u>
Then, 10.93 grams of CO₂ are formed when 8.50 g of methane react with 15.9 g of O₂.
Learn more about the reaction stoichiometry:
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Gamma is not affected by both fields because it isnt charged.
Only alpha and beta ray will be affected because they are charged with positive and negative ions respectively.
In otherwords, <span>Gamma rays are high-energy photons of light, which have zero electric charge. So they are not affected by magnetic fields</span>
Here's a chart. .
If that doesnt help tell me :)
Only alpha and beta ray will be affected because they are charged with positive and negative ions respectively.
In otherwords, <span>Gamma rays are high-energy photons of light, which have zero electric charge. So they are not affected by magnetic fields</span>
Here's a chart. .
If that doesnt help tell me :)