Question

Ammonium carbonate NH4CO2NH2 decomposes as follows

Answer 1

Answer:

Kp = 0.0146

Explanation:

We can solve this equilibrium problem using an ICE Table. There are 3 stages: I(Initial), C(Change) and E(Equilibrium). Only gases and aqueous species participate in the equilibrium.

    NH₄CO₂NH₂ ⇄ 2 NH₃(g) + CO₂(g)

I                                    0             0

C                                 +2x          +x

E                                   2x            x

Total gas pressure is equal to the sum of partial pressures at equilibrium.

pNH₃ + pCO₂ = 0.463 atm

 2x    +     x     = 0.463 atm

 3 x = 0.463 atm

    x = 0.154 atm

Then,

pNH₃ = 0.308 atm

pCO₂ = 0.154 atm

We can replace this data in the Kp expression.

$Kp=pNH_{3}^{2} \times pCO_{2} =0.308^{2} \times 0.154 = 0.0146$