What is the equation in slope-intercept form of a line that is perpendicular to y=1/4x−1 and passes through the point (4, 1)?
2 answers:
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Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
+6=perimeter
Hope that helps :)
Answer:
There is no solution to this equation that is an integer for x.
Step-by-step explanation:
x is the first integer, and x+1 the second