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loris [4]
3 years ago
7

Help me pls i have no idea how to do this :(((((((

Mathematics
1 answer:
den301095 [7]3 years ago
3 0
For all just put them together in x and y. For example, f(2)=-2 would be (2,-2). f(1)= 1 would be (1,1).
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Find the quotient. Simplify completely. Please show work.
nadya68 [22]

1. 8/9 ÷ 4/9 is done by inverting the divisor (4/9) and then multiplying:

(8/9)(9/4) = 8/4 = 2 (answer)

2. 1/3 ÷ 6 is done similarly: (1/3)(1/6) = 1/18 (answer)

3. 4 ÷ 1/5 = 4 * 5 = 20 (answer)

4. 7 1/2 ÷ 1/4 = (15/2)(4/1) = 30 (answer)

8 0
3 years ago
PLEASE HELP?!
Anon25 [30]
The middle point of BC is (0,2), the midpoint of CD is (1,0)
to prove two lines are parallel, prove their slopes are the same.
slope of BD: m=rise/run=4/-2=-2 (the run is negative because to get to B from D on the grid, you have to move from right to left, then upward. If the horizontal move is from left to right, the run is positive)
slope of EG: m=rise/run=2/-1=-2 
EG and BD have the same slope, so they are parallel. 
3 0
4 years ago
Helpppppppppppppppppp
harkovskaia [24]

Answer:

Answer choice B

Step-by-step explanation:

When you factor the equation, 12 only has 6x2 to equal the -12x. This means that you'll factor it into (3x-6)(x-2). When you set either of these equal to 0, the x value is 2.

8 0
3 years ago
Dario buys applesauce for a family reunion. He needs 23 cups, and he buys them in packs of 6. How many packs does Dario need?
hodyreva [135]
He has to buy 4 packs. If you divide 23 by 6, you get 3.833 but you can’t buy a fraction of a pack so you have to round up and buy 4 packs. Hope this made sense; I can explain further if needed!
4 0
3 years ago
Can someone solve this?
ladessa [460]
  • First question:

Recall that \cos^2x+\sin^2x=1 and \sqrt{x^2}=|x| for all x. So

\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|

\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|

For 0, we expect both \cos x>0 and \sin x>0 (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, |x|=x if x>0.

So we have

\dfrac{\sqrt{1-\cos^2x}}{\sin x}+\dfrac{\sqrt{1-\sin^2x}}{\cos x}=\dfrac{\sin x}{\sin x}+\dfrac{\cos x}{\cos x}=1+1=\boxed{2}

making H the answer.

  • Second question:

C is always true, because the inequality reduces to x > y.

6 0
4 years ago
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