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loris [4]
3 years ago
7

Help me pls i have no idea how to do this :(((((((

Mathematics
1 answer:
den301095 [7]3 years ago
3 0
For all just put them together in x and y. For example, f(2)=-2 would be (2,-2). f(1)= 1 would be (1,1).
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A man weighing 800 N is hanging from a 2 mm diameter titanium wire with a cross-section of 3 x 10^-6 m^2. Will the wire break?
DENIUS [597]

Answer:

Since stress is greater than ultimate strength, the wire will break.

Step-by-step explanation:

The titanium wire is experimenting an axial load. Ultimate strength equals 2.20\times 10^{8}\,Pa. The wire shall break if and only if stress is at least equal to ultimate strength. The equation for axial stress (\sigma), measured in pascals, in the wire with circular cross-section is:

\sigma = \frac{4\cdot F}{\pi\cdot D^{2}} (1)

Where:

F - Axial force, measured in newtons.

D - Cross-section diameter, measured in meters.

Please notice that axial force is the weight of the man hanging from wire.

If we know that F = 800\,N and D = 0.002\,m, then the axial stress experimented by the titanium wire is:

\sigma = \frac{4\cdot (800\,N)}{\pi\cdot (0.002\,m)^{2}}

\sigma \approx 2.546\times 10^{8}\,Pa

Since stress is greater than ultimate strength, the wire will break.

3 0
3 years ago
2, 5, 9, 14, ?, 27. what’s the missing number?
poizon [28]

Answer:

20

Step-by-step explanation:

2, 5, 9, 14, ?, 27.

2,5 the number added is 3

5,9 the number added is 4

9,14 the number added is 5

14,20 the number added is 6

20 , 27 the number added is 7

7 0
3 years ago
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Which number, when placed in the box, will make the equation true?<br> _^2 =square root of 64
velikii [3]
The answer is 8✊✊✊✊✊✊✊✊✊
4 0
3 years ago
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How do I rewrite the improper fractions as a mixture number? Please explain step by step to get marked as brainliest
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Answer:

1) Divide the numerator by the denominator.

2) Write down the whole number result.

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Step-by-step explanation:

not sure of this will help... but hope it does!

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3 years ago
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\huge \bf༆ Answer ༄

Let's solve ~

\qquad \looparrowright \sf - 2 \sqrt{192 {k}^{4} }

\qquad \looparrowright \sf - 2 \sqrt{2 {}^{6} \times   3{k}^{4} }

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Hence, the correct choice is D

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3 years ago
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