All categories

2 years ago

ON A TIME LIMIT PLS HELP!!!! thank youu

Mathematics

1 answer:

Slav-nsk [51]2 years ago

5 0

Answer:

RQS=110

TQS=70

Step-by-step explanation:

(12x+2)+(7x+7)=180

The two equations added together give us a straight line which is angle 180

19x + 9 = 180

19x = 171

We solve for x

x = 9

Now that we have x we plus in to each equation

RQS= (12(9)+2)

= 110

TQS=(7(9)+7)

=70

You might be interested in

How do I do regular fractions and equivalent fractions

jenyasd209 [6]

Regular= 3/5 equivalent= 6/10 just multiply the top and bottom by the same number.

8 0

2 years ago

Read 2 more answers

Camila and Evelyn work at a dry cleaners ironing shirts.Camila can iron 40 shirts per hour, and Evelyn can iron 20 shirts per ho

GalinKa [24]

60 shirts can be ironed per hour with two workers

8 0

3 years ago

Read 2 more answers

Subtract: (4n + 7) - (7n - 8)

Furkat [3]

4n+7−(7n−8)

=4n+7+−1(7n−8)

=4n+7+−1(7n)+(−1)(−8)

=4n+7+−7n+8

Combine Like Terms

=4n+7+−7n+8

=(4n+−7n)+(7+8)

=−3n+15

4 0

2 years ago

A floor is made up of 20 triangular tiles, each with sides 40 cm, 24 cm and 32 cm. Find the cost of polishing the floor at the r

pochemuha

Answer:

$15360\,\,rupees$

Step-by-step explanation:

Let sides of the triangle be $a,b,c$

$a=40\,,\,b=24\,,\,c=32$

Semi-perimeter (s) = $\frac{a+b+c}{2}$

$=\frac{40+24+32}{2}\\ =\frac{96}{2}\\=48$

Area of one tile $=\sqrt{s(s-a)(s-b)(s-c)}$

$=\sqrt{48(48-40)(48-24)(48-32)}\\ =\sqrt{48(8)(24)(16)}\\ =\sqrt{147456} \\=384\,\,cm^2$

So,

Area of 20 tiles $=20(384)=7680\,\,cm^2$

Cost of polishing the floor at the rate of 2 rupees per sq.cm = $7680(2)=15360\,\,rupees$

7 0

2 years ago

What percent is 15 out of 500?

7nadin3 [17]

Answer:

Step-by-step explanation:

P% = 15/500

P = 0.03

P% = 0.03 * 100 = 3%

3 0

1 year ago

Read 2 more answers