Answer:
The number of nickels is 45 and the number of dimes is 72.
Step-by-step explanation:
Let
x ----> number of nickels
y ----> number of dimes
Remember that
so
------> equation A
------> equation B
<em>Solve the system by substitution</em>
we have
------> equation A
------> equation B
Multiply both equations by 100 both sides
---->
--> equation C
----> equation D
substitute equation C in equation D
solve for y
Find the value of x
<em>Alternative Method</em>
Solve the system by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
the solution is the point (45,72)
therefore
The number of nickels is 45 and the number of dimes is 72.
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So there are five candy bars.
Herself and two sisters equals 3 people in total.
This is a graph of 5 candy bars, each line being 1/2.
━ ━
━ ━
━ ━
━ ━
━ ━
If she ate half of one... the graph would become this.
━ ━
━ ━
━ ━
━ ━
━
Now there are 9 halves. You need to split the 9 halves for 3 people. 9 divided by 3 is 3.
Each person gets 3 halves, or 1 and 1 half.
Mai: ━ ━ ━
Sister 1: ━ ━ ━
Sister 2: ━ ━ ━
Altogether that is 9 halves, AKA the number of halves Mai had after she ate 1/2.
The amount Mai ate in the first place: ━
9 halves plus 1 half, equals 10 halves. Each whole has 2 halves. 10 divided by 2 is 5, AKA the number of candy bars she had in the first place.
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You need to write it out such as number 8 would be 10x10x10x10 so for every number on top you multiply the number by itself
Answer:
The correct option is;
3 + (-9) = -6, because -6 is 9 units to the left of 3
Step-by-step explanation:
The given information are;
Kelvin's score after the first round is shown at point K on the number line
The range of numbers on the number line = -10 to +10
The position of point K after the first round = +3
The number of points Kevin lost in the second round = 9 points
Therefore, Kevin's cumulative score = +3 - 9 = -6
Therefore, the expression that shows how many total points he has at the end is of round 2 = 3 + (-9) = -6, because -6 is 9 units to the left of 3.
