This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
</u><u /><u />
If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
You have to multiply by the complex conjugate so that you can clear the radical from the denominator.
Once you do the multiplication simplify the radical. There's still a common factor in -54, -18, & 75 so divide all those by 3.
48 sq. Units
If I’m wrong I’m truly sorry
Answer:
5
Step-by-step explanation:
keep, change, flip
2/1 (keep) x (change to multiply) 5/2(2/5 flips to 5/2)
2/1 x 5/2
10/2
5
120 is the right answer that is what my teacher told me
