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LiRa [457]
3 years ago
12

Thę grades on a math midterm at Springer are roughly symmetric with u = 72 and 0 = 4.5.

Mathematics
1 answer:
m_a_m_a [10]3 years ago
6 0
Hwhiwbshs
bengshhwwvvw
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if a, b, and c are prime numbers, do (a b) and c have a common factor that is greater than 1? (1) a, b, and c are all different
klio [65]

If a,b, and c are prime numbers, do (a*b) and c have a common factor that is greater than 1

(1) a,b, and c are all different prime numbers

(2) c≠2

1. Let's assume values of 1,3 and 5 to a, b, and c respectively

a b = 1*3 = 3

3 and 5 do not have any common factor aside 1

Let's assume values of 1,3 and 2 to a,b and c respectively

a *b = 1*3 = 3

3 and 2 does not have a common factor aside 1

2. c \neq 2

Let's assume values of 2,7 and 3 to a b and c response

a * b = 2 *7 = 14

14 and 3 does not have a common factor aside 1

learn more about of prime number here

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1 year ago
Which statement about the area of a right triangle is true?
timurjin [86]

Answer:

H

Step-by-step explanation:

This is because a rectangle can be divided into two triangles.

5 0
3 years ago
6 3/4 % 5 1/2<br><br> This % means divided by
yuradex [85]
Divided by the 5 1/2
8 0
3 years ago
Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)
BigorU [14]
For a moment, let y=x^2-2x+5. Then by the distributive property,

(2x^2+4x-3)p=2x^2p+4xp-3p


Again by the distributive property,

2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2

4xp=4x(x^2-2x+5)=4x^3-8x^2+20x

-3p=-3(x^2-2x+5)=-3x^2+6x-15

Taking everything together, we get

(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)
(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15
7 0
4 years ago
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X−6&gt;−2 solve the inequality
hjlf

Answer:

x>4

Step-by-step explanation:

3 0
3 years ago
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