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Vikki [24]
3 years ago
8

Expand and simplify (2x+1) (x-2) (x+3)

Mathematics
2 answers:
nadezda [96]3 years ago
7 0

Answer:

2x^3 + 3x^2 - 11x - 6.

Step-by-step explanation:

(2x+1) (x-2) (x+3)

= (2x + 1)[x(x + 3)-2(x + 3)]

= (2x + 1)(x^2 + x - 6)

= 2x(x^2 + x - 6) + 1(x^2 + x - 6)

= 2x^3 + 2x^2 - 12x + x^2 + x - 6

= 2x^3 + 3x^2 - 11x - 6.

Mnenie [13.5K]3 years ago
6 0

Good morning,

Answer:

<h2>=2x³+3x²-11x-6.</h2>

Step-by-step explanation:

(2x+1) (x-2) (x+3)

= (2x+1) [(x-2) (x+3)]

= (2x+1) [x²+3x-2x-6]

= (2x+1) [x²+x—6]

= 2x³+2x²-12x+x²+x-6

=2x³+3x²-11x-6.

:)

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Write an equation in standard form that is parallel to the line y = 2x - 1 that passes through the point (1, 2). 2x - y = 0 O x
timofeeve [1]

Answer:

2x - y = 0

Step-by-step explanation:

The equation of a line in slope- intercept form is

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y = 2x - 1 ← is in slope- intercept form

with slope m = 2

Parallel lines have equal slopes, thus

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To find c substitute (1, 2) into the partial equation

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y = 2x ← equation in slope- intercept form

Subtract y from both sides

0 = 2x - y , that is

2x - y = 0 ← equation in standard form

5 0
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4 0
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