Rewrite each expression with positive exponents. simplify if possible .

Determine whether quantities vary directly or inversely and find the constant of variation. If 5 bushels of wheat weigh 136 kg,

pentagon [3]

Let the bushels of wheat is b and weight of the wheat is w.

We can say that more the bushels of wheat more will be the weight of the wheat.

Hence, the quantities vary directly.

Therefore, we have

$b=kw$ , where k is the constant of variation.

Now, we have been given that 5 bushels of wheat weigh 136 kg. Thus, we have

$5=136k\\
\\
k=\frac{5}{136}$

Thus, the constant of variation is $\frac{5}{136}$

Now, we have been given 3.5 bushels of wheat. Hence, we have

$3.5=\frac{5}{136} w\\
\\
w=\frac{136\times 3.5}{5} \\
\\
w=95.2$

Therefore, 3.5 bushels of wheat weigh 95.2 kg

4 0

4 years ago

Read 2 more answers

Pls help i only have 2 minuets left

Sveta_85 [38]

Answer:

14, 3!

Step-by-step explanation:

It is very complicated to explain.

4 0

3 years ago

Christopher's best time in a race is four seconds faster than his second-best time. his second best time is 1 1/3 times slower t

a_sh-v [17]

If his best time is x, and the best time is smaller, then (1+1/3)*x=his second best time. If x+4=his second best time (since his second best time is 4 seconds slower), then (1+1/3)*x=x+4. Multiplying it out, we get (3/3+1/3)*x=x+4
=4x/3=x+4. Subtracting x from both sides, we get 4x/3-3x/3=x/3=4. Multiplying both sides by 3, we get x=12=his best time

8 0

4 years ago

How many different 11-letter arrangements can be made using the letters in the word Firecracker?

zhenek [66]

Answer:

Total number of arrangements = 1,663,200

Step-by-step explanation:

Given:

11 - letter

FIRECRACKER

F = 1

I = 1

R = 3

E = 2

C = 2

A =1

K = 1

Find:

Total number of arrangements = ?

Computation:

Note: Repeated letter will be avoid.

$Number\ of\ arrangements = \frac{!11}{!3 \times !2 \times !2}\\\\Number\ of\ arrangements = \frac{!11}{!3 \times !2 \times !2} \\\\Number\ of\ arrangements = \frac{11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3}{3 \times 2 \times 2 } \\\\Number\ of\ arrangements = 1,663,200$

Total number of arrangements = 1,663,200

6 0

4 years ago

Find all real and non-real roots of the function ƒ(x) = x2 + 49. Question 1 options: A) x = –7, 7 B) x = –7i, 7i C) x = –49i, 49

dimulka [17.4K]

Answer:

B

Step-by-step explanation:

f(x) = x²+49 , rewrite the equation

x² +7² =0 , to find the roots make f(x) =0 and subtract 7² from both sides

x² = -7², square root both sides

√x² =√-7², consider √-1 =i

x= ±7i

the roots are -7i and 7i

3 0

3 years ago

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