Answer:
The probability of the spinner landing on A is 0.1111.
Step-by-step explanation:
The possible outcomes of a board game is that it can lead on any three of the regions, A, B and C.
The probability of all the outcomes of an event sums up to be 1.

According to the provided information:
P (B) = 3 P (A)
P (C) = 5 P (A)
Compute the probability of the spinner landing on A as follows:

Thus, the probability of the spinner landing on A is 0.1111.
You do 18.6 ÷ 3 and that equals 6.2
I think is D , hope i answer fast enough haha :D
Answer:
9
Step-by-step explanation:
3/2x6/2=18/2 Simply that and it turns to 9.
X=9
A) 3x-7=34
3x= 34+7
3x= 41
x= 41/3
B) x-9=1
x=1+9
x=10
C) dude what is this
D) 4x+5=41
4x=41-5
4x=36
x=36/4
x=9 YAYY
Hope it helps!
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