Answer: B. 34°
<u>Step-by-step explanation:</u>
∠RQS + ∠SQT = ∠RQT
Answer:
40
Step-by-step explanation:
Answer:
Let's talk through this a one step at a time.
*Since f(x) is concave-up with its vertex on the x-axis, we know f(x) ≥ 0.
*We also know that when we shift a function's domain by a positive number, we shift the function left and when we shift a function's domain by a negative number, we shift the function right. So f(x-5) is f(x) shifted to the right by 5.
*At this point, f(x-5) has its vertex at (5,0).
*When we negate f(x-5), the parabola becomes concave down yet the vertex remains at (5,0). Now we're at -f(x-5). At this point we have -f(x-5)≤0 with a range (-∞,0]
*If we add 2 to create g(x)=2-f(x-5), then we have a concave down parabola with its vertex shifted up by 2, at (5,2). So, g(x) is concave down with its vertex at (5,2). Hence
Answer:5
Step-by-step explanation:
I said that because I just divide
It is C.
If you type in your calculator "Y=" and then " -4(2)^x " and click "GRAPH" you will see a descending graph, from left to right, that looks EXACTLY like the third graph in option C.
