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aleksklad [387]
2 years ago
11

\frac{7}{4} \frac{13}{2}[/tex]

Mathematics
2 answers:
Thepotemich [5.8K]2 years ago
7 0

Answer:

(7/4) × (13/2)

→ (7×13/(4×2)

→ (91/8) Ans.

Margarita [4]2 years ago
5 0

Answer:

Solution given:

\frac{7}{4} * \frac{13}{2}=\frac{7*13}{4*2}=\frac{91}{8}

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A closed cylindrical tank of radius 1.50m and height 300cm, is made from a metal sheet. How much sheet is required?
Anika [276]

Answer: 13.5π≈42.41

Step-by-step explanation:

Basically it is asking for the circumference of this cylinder.

#1 Find the circumference of the circle base

Formula to use: 2πr

2πr=2π(1.5)=3π

---------------------------

#2 Find the area of the circle base

Formula to use: πr²

πr²=π(1.5)²=2.25π

--------------------------

#3 Find the area of body of the cylinder

Formula to use: lw

300cm=3m

l (length)= 3π (since the body of the cylinder the basing on the circumference of the circle base)

w (width)= 3

lw=3π×3m=9π

----------------------------

#4 Add all of them together

There are 2 base and one body

2.25π×2+9π=13.5π

4 0
3 years ago
What is the mistake loki made?
DerKrebs [107]
Answer:
Loki didn’t square a and b

Answer explained:
Pythagorean Theorem is a^2 + b^2 = c^2
5 0
3 years ago
PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE HELP
Nataliya [291]

Answer:

please help me my friend

5 0
2 years ago
Find a homogeneous linear differential equation with constant coefficients whose general solution is given by
frez [133]

Answer:

y" + 2y' + 2y = 0

Step-by-step explanation:

Given

y=c_1e^{-x}cosx+c_2e^{-x}sinx

Required

Determine a homogeneous linear differential equation

Rewrite the expression as:

y=c_1e^{\alpha x}cos(\beta x)+c_2e^{\alpha x}sin(\beta x)

Where

\alpha = -1 and \beta = 1

For a homogeneous linear differential equation, the repeated value m is given as:

m = \alpha \± \beta i

Substitute values for \alpha and \beta

m = -1 \± 1*i

m = -1 \± i

Add 1 to both sides

m +1= 1 -1 \± i

m +1= \± i

Square both sides

(m +1)^2= (\± i)^2

m^2 + m + m + 1 = i^2

m^2 + 2m + 1 = i^2

In complex numbers:

i^2 = -1

So, the expression becomes:

m^2 + 2m + 1 = -1

Add 1 to both sides

m^2 + 2m + 1 +1= -1+1

m^2 + 2m + 2= 0

This corresponds to the homogeneous linear differential equation

y" + 2y' + 2y = 0

6 0
3 years ago
Good at math, help please!!!!!!
solmaris [256]
C is tevanswer out I think so
6 0
3 years ago
Read 2 more answers
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