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Allushta [10]
2 years ago
9

Need help with these questions

Biology
1 answer:
Illusion [34]2 years ago
5 0

Answer:

foto yg kamu pilih sesuai yg kamu mau

Explanation:

vidio yg paling masuk dengan soal

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Jack has just returned after a walk in the woods. He finds several sticky weed seeds stuck to his jersey with their sharp hooks.
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The reason is to help in seed dispersal. Seed dispersal is the movement or transport of seeds away from the parent plant. Due to the fact that plants have very limited mobility they have to rely upon variety of dispersal; vectors to transport their seeds, including both abiotic and biotic factors. Seed dispersal is important because if seed are not dispersed, many germinating seedlings will grow very close to the parent plant which would result to competition between every one of the seedlings as well as the parent. The competition for essential growth factors such as light, space, water and nutrients. 
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Which of the following statements is true concerning humans?
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We can’t answer if that’s all u give us
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Map One method for separating polypeptides makes use of their different solubilities. The solubility of large polypeptides in wa
PSYCHO15rus [73]

Answer: For (a):

(Lys-Ala)3 is soluble and (Gly)zo is not soluble.

(b) (Glu)zo is soluble and (Phe-Met) is not soluble.

(c) ( Asn-Ser-His) is soluble and (Ala- Asp-Gly) is not soluble.

(d) (Asn-Ser-His) is soluble and (Ala-Ser-Gly).

Explanation:Firstly, the solubility of polypeptides relies on polar groups in the R group of the side chain and also ionized groups because these groups can interact with dipole bond of water.

For (a): (Gly)zo, no R group of the side chain of (Gly)zo is polar nor ionizable and solubility is based on the ability of R group of polypeptides to be polar or ionized while in polypeptides of (Lys-Ala), Lys is polar and therefore soluble though Ala in the compound is not polar nor ionizable but the presence of Lys makes the polypeptide to be soluble.

(b) (Glu)zo is a polar peptide, therefore soluble peptides while both the combination of (Phe-Met)3 gives polypeptides that are not polar therefore not soluble.

(c) In poypeptide of (Ala-Asp-Gly)s, the R group on the side chain of both Ala and Gly are neither polar nor ionizable therefore cannot be soluble even though Asp( which at PH 3 can partially be protonated and partially deprotonated to make it soluble) is present in the polypeptide. Therefore the polypeptide of Ala-Asp-Gly is not soluble compared to Asn- Ser-His, where Asn has polar covalent bond which can interact with water, His which at pH 6 will be half protonated and half deprotonated making the substance to react with water and also Ser is a soluble polypeptide too.

(d) Also between (Ala- Ser-Gly) and ( Asn- Ser-His), polypeptide with (Asn-Ser-His) will be considered soluble because Ala and Gly have R groups that neither polar nor ionizable though Ser is soluble but common to both substances, its influence will not be effective and (His) is a soluble which at pH 6 get partially protonated and deprotonated.

3 0
3 years ago
Distilled water is _____ or _______ to the solution inside a cell
fgiga [73]

Answer:

hypertonic or hypotonic

Explanation:

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The thin filaments and thick filaments and their associated proteins are the key functional components of the sarcomere. it is i
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Muscle is composed of small units known as myofibril which itself composed of cylindrical bundles of thread like filaments; thick filament and thin filament known as myosin and actin respectively.

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The function of the muscle is to contract and these filaments play a major role in it


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