(10 points!!!) AND I’LL MAKE YOU BRAINLEST

A roast turkey is taken from an oven when its temperature has reached 185°F and is placed on a table in a room where the tempera

ANEK [815]

It is very important to look at the graph very minutely. It can be seen that at 30 minutes the slope is a little more than negative 50 and at <span>90 minutes it is a little less than negative 50. From this fact, it can be deduced that the estimated rate of </span><span>change of the temperature after an hour would be -50/60. I hope that the answer has come to your desired help.</span>

8 0

3 years ago

Sarah claims that the thickness of the spearmint gum she produces is 7.5 one-hundredths of an inch. A quality control specialist

satela [25.4K]

Answer:

$t=\frac{7.55-7.5}{\frac{0.103}{\sqrt{10}}}=1.539$

$p_v =2*P(t_{(9)}>1.539)=0.158$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis.

Step-by-step explanation:

Data given and notation

Data: 7.65, 7.60, 7.65, 7.7, 7.55, 7.55, 7.4, 7.4, 7.5, 7.5

We can begin calculating the sample mean given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And the sample deviation given by:

$s=\sart{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And we got:

$\bar X=7.55$ represent the sample mean

$s=0.103$ represent the sample standard deviation

$n=10$ sample size

$\mu_o =7.5$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal to 7.5 or no, the system of hypothesis would be:

Null hypothesis: $\mu = 7.5$

Alternative hypothesis: $\mu \neq 7.5$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{7.55-7.5}{\frac{0.103}{\sqrt{10}}}=1.539$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=10-1=9$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(9)}>1.539)=0.158$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis.

3 0

3 years ago

You have an equation y=x+7. Is the ordered pair (1,6) a solution? Yes or no?

vaieri [72.5K]

Answer:
no

step-by-step explanation:
y=x+7
x is the slope of 1
7 is the y-intercept
because 7 is the y-intercept and the slope is positive it never touches (1,6)

8 0

2 years ago

Пожалуйста помогите с решением

zubka84 [21]

Answer:

( x, y) =

$65 \ \frac{15}{11}$

this is your answer

3 0

2 years ago

HELP PLS ILL MARK BRAINLIEST

Lunna [17]

Answer:

3rd one

Step-by-step explanation:

3 0

3 years ago