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If two similar triangles have sides in the ratio a : b, then their areas are in the ratio a² : b².
We have the ratio:
Area of the smaler triangle = x
Area of the larger triangle = 567 cm²
Therefore we have the equation:
Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that
Putting , we get
Therefore, the measure of angle RQP is 33 degrees.
Answer:
x^2+8x
Step-by-step explanation:
instructions included above :)
