16 thru 23 look wrong and 16 is absolutely wrong. You use this:https://www.mathpapa.com/algebra-calculator.html to work out the answers and it shows the steps and explains it to you better than I could. Good luck
1. Using your straightedge, draw a reference line, if one is not provided.
2. Copy the side of the square onto the reference line, starting at a point labeled A'.
3. Construct a perpendicular at point B' to the line through ab2.
4. Place your compass point at B', and copy the side of the square onto the perpendicular b'g. Label the end of the segment copy as point C.
5. With your compass still set at a span representing AB, place the compass point at C and swing an arc to the left.
6. Holding this same span, place the compass point at A' and swing an arc intersecting with the previous arc. Label the point of intersection as D.
7. Connect points A' to D, D to C, and C to B' to form a square.
Answer:
and the domain is the set of
Step-by-step explanation:
1. 5x+ 2(x+6)
= 5x+ 2x+ 2*6 (distributive property)
= 5x+ 2x+ 12
= (5x+ 2x)+ 12 (combine like terms)
= 7x+ 12
The correct answer is C. 7x+12~
2. <span> -3m + 3(m + 6)
= -3m+ 3m+ 3*6
= -3m+ 3m+ 18
= (-3m+ 3m)+ 18
= 18
The correct answer is D. 18~</span>
This means that all of the points are co-linear. This is because if EG is a segment that contains F, and EN is a segment that contains M, then there can be two different segments. However, for a point F on the first segment and a point M on a second segment be in the same line as an end point of one of the segments, the segments have to be co-linear. They overlap.
