Answer:
The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction
Step-by-step explanation:
- For a constant acceleration:
, where
is the final velocity in a direction after the acceleration is applied,
is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied. - <em>Then for the x direction</em> it is known that the initial velocity is
5320 m/s, the acceleration (the applied by the engine) in x direction is
1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: 
- In the same fashion, <em>for the y direction</em>, the initial velocity is
0 m/s, the acceleration in y direction is
7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: 
Answer:
Step-by-step explanation:

b.
an=an-1+3
C.
when x=15
y=3×15-2=45-2=43
a15=43
Answer:
16
Step-by-step explanation:
Let "a" represent the measure of the angle. Then ...
5a -30 = 2a +18
3a = 48 . . . . . . . add 30-2a
a = 16 . . . . . . . . . divide by 3
An angel is beyond measure, but this angle has measure 16.
Answer:
5 times as many should be your answer.