Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
<span>standard form of a linear equation
is ax+by+c=
y=2x
y-2x=0
</span>
Answer:
The answer is (A)
Step-by-step explanation:
:D
Answer:
The radius of the circles are 
and 
Step-by-step explanation:
Let
x-----> the radius of larger circle
y----> the radius of smaller circle
we know that
-----> equation A
Remember that
-----> equation B
substitute equation B in equation A and solve for y
Find the value of x
therefore
The radius of the circles are and
<span>The total cost for Glenn Andrews is the value of the motorbike plus the sales tax. The sales tax is found multiplying the value times the percent sales tax rate, divided by 100. This is, tax sales = $3950 * 6% = $ 3950 * 6 /100 = 237. And the total cost was $ 3950 + $237 = $4187.</span>
