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2 years ago

(Will give 25 points) Given the graph of this trigonometic funaction over which domain(s) could inverse function be constructed

Mathematics

1 answer:

GREYUIT [131]2 years ago

5 0

Answer:

ok so i think it it a or b i don't know but hope i am right

Step-by-step explanation:

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In a certain region, the number of children who have been vaccinated against rubella is twice the number who have been vaccinate

MatroZZZ [7]

Answer:

C. 10 000

Step-by-step explanation:

If we called:

x = children who have been vacinated against rubella only

2x = children who have been vaccinated against mumps

y = children who have been vaccinated agains both

Children who have been vaccinated against mumps only = x - y

And we know that y = 2*(x-y)

=> 2y = 3x

y = 5000

There fore x = 7500

The number of children who have been vaccinated against rubella

= 2x - y = 2*7500 - 5000 = 15 000 - 5000 = 10 000

4 0

3 years ago

Which costs the most: 12 cat toys, 4 bags of cat food, or 3 litter boxes? Explain.

lukranit [14]

Answer:

3 litter boxes

Step-by-step explanation:

It depends what type it is

7 0

2 years ago

Any 10th grader solve it <br>for 50 points

kkurt [141]

Answer:

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0$ is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., $a_{1}=A$ and common difference=D

The nth term can be written as

$a_{n}=A+(n-1)D$

pth term of given arithmetic progression is a

$a_{p}=A+(p-1)D=a$

qth term of given arithmetic progression is b

$a_{q}=A+(q-1)D=b$ and

rth term of given arithmetic progression is c

$a_{r}=A+(r-1)D=c$

We have to prove that

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0$

Now to prove LHS=RHS

Now take LHS

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)$

$=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)$

$=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)$

$=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}$

$=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}$

$=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}$

$=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2}-pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}$

$=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2} -pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}$

$\neq 0$

ie., $RHS\neq 0$

Therefore $LHS\neq RHS$

ie., $\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0$

Hence proved

5 0

2 years ago

A house purchased for $230,000 has lost 6% of its value each year for the last four years. What is the house worth now?

lutik1710 [3]

You can use the compound growth to work this out,

Firstly you need to make a multiplier for -6%;
1-(6/100) = 0.94

The you times the amount of money by 0.94 to the power of 4 because you are working out 4 years:
230000*0.94^4 = 179527.26

The answer is $179527.26,
Hope this helps! :)

3 0

2 years ago

The volume code of a cube is given by s to the third power, where s is this side length of the cube. What is the difference of t

yKpoI14uk [10]

Answer:

61 m^3

Step-by-step explanation:

The difference in volume is (5 m)^3 - (4 m)^3, or (125 - 64) m^3, or

61 m^3

6 0

2 years ago

Read 2 more answers