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Oksana_A [137]
2 years ago
13

you have 36 pages to read for homework . in 5 minutes you read 10 pages. if you continue to read at the same rate how many minut

es will it takes you to read all 36 pages.
Mathematics
2 answers:
Stella [2.4K]2 years ago
6 0

Answer:

72 minutes

Step-by-step explanation:

It takes you 5 minutes to read 10 pages so to read 1 page it would take 10÷5= 2 minutes, therefore 36 pages will = 36 × 2 which is 72 minutes.

Novay_Z [31]2 years ago
5 0
Answer: 18 minutes
10+10+10= 30 = 15 minutes 2 pages per minute = 3 minutes for 6 pages
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How do you solve -k/5 times 7/5
Firdavs [7]

Answer:

\frac{-7}{25}k

Step-by-step explanation:

\frac{-k}{5} *\frac{7}{5}

just multiply across

-k*7=-7k

5*5=25

\frac{-7}{25}k

hope this helps

5 0
2 years ago
A gym charges a $59 fee plus $7.70 per week that person attends. The total cost y for any number of weeks x can be given using t
lianna [129]
Firstly the equation would be y=7.7x+59
(A)The slope is 7.7 (B) and shows that there is a 7.7 charge per week the person attends.
(A)The y intercept is 59 (B) and is the initial fee that the gym charges.
8 0
3 years ago
The length of a football field is 120m. what is the length on drawing, if the scale is 1:5m?​
inna [77]
Answer: I believe its 24 meters.
Explanation: Just divide 120 by 5
5 0
3 years ago
How many 5-millimeter-long spiders would it take to make a line of spiders 1 meter long?
Bogdan [553]

Answer:

1000

Step-by-step explanation:

10milimeter=1 centimeter

100 centimeters=1 meter

10x100=1000

Let me know if im right :)

3 0
3 years ago
Kindly answer this one. Thank you.​
steposvetlana [31]

Answer:

See below.

Step-by-step explanation:

I'm assuming these questions are about the Midline Theorem (segment AL joins the midpoints of the non-parallel sides.

♦  The midline's length is the average of the lengths of the top and bottom parallel sides.

AL=\frac{OR+CE}{2}

Use this equation and substitute values given in each problem, then solve for the missing information.

1. AL = x, CE = 9, OR = 5

x=\frac{9+5}{2}=7

2. AL = <em>m</em> - 4, CE = 15, OR = 17

m-4=\frac{15+17}{2}=16\\\\m-4=16\\\\\\m=20\\\\AL=20-4=16

3. OR = y + 5, AL = 15, CE = 18

15=\frac{(y+5)+18}{2}\\\\15=\frac{y+23}{2}\\\\30=y+23\\\\7=y\\\\OR = 7+5=12

4 0
2 years ago
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