Answer and step-by-step explanation:
20. Because the discount is 20% of the given price so the discount would be"
228/100*20
= 45.6 Rs
Its selling price would be:
228 + 45.6 = 273.6 Rs
21. Sales tax would be:
450/100*5
= 22.5 Rs
Total price in bill = 22.5 + 450 = 472.5 Rs
22. 10% tax of 3300 would be:
3300/100*10 = 330 Rs
Price before tax = 3300 - 330 = 2970 Rs
23. He spent in total of:
2500 + 500 = 3000Rs
He sold for 3300 Rs
He gain 3300 - 3000 = 300 Rs profit
His loss gain percent = 3300/3000 * 100 = 110%
24. On the first bike, he earn:
2500/100*20 = 500 Rs
On the second bike, he lose:
2500/100*25 = 625 Rs
He lose in total of 625 -500 = 125 Rs
his loss percentage = (2500+500) + (2500 - 625) / 5000* 100
= 100% - (2500+500) + (2500 - 625) / 5000* 100
= 100% - 97.5%
He lose 2.5% money
Hope this helped :3
Answer:
Step-by-step explanation:
For this case we are interested on the region shaded on the figure attached.
And we can find the volume with the method of rings.
The area on this case is given by:
![A(x) = \pi [f(x)]^2 = \pi r^2 = \pi [3x]^2 = 9\pi x^2](https://tex.z-dn.net/?f=%20A%28x%29%20%3D%20%5Cpi%20%5Bf%28x%29%5D%5E2%20%3D%20%5Cpi%20r%5E2%20%3D%20%5Cpi%20%5B3x%5D%5E2%20%3D%209%5Cpi%20x%5E2)
And the volume is given by the following formula:

For our case our limits are x=0 and x=2 so we have this:

And if we solve the integral we got this:
![V= \pi [\frac{x^3}{3}]\Big|_0^{2}](https://tex.z-dn.net/?f=%20V%3D%20%5Cpi%20%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%5D%5CBig%7C_0%5E%7B2%7D)
And after evaluate we got this:
![V=\pi [(\frac{8}{3} )-(\frac{0}{3} )]](https://tex.z-dn.net/?f=%20V%3D%5Cpi%20%5B%28%5Cfrac%7B8%7D%7B3%7D%20%29-%28%5Cfrac%7B0%7D%7B3%7D%20%29%5D)
9 groups of 4 students each = (9 x 4) = 36
6 groups of 6 students each = (6 x 6) = 36
Answer:

Step-by-step explanation:
tan is defined as: 
sin is defined as: 
cos is defined as: 
We can also define tan as: 
because plugging in the definitions of sin and cos in we get: 
which you'll notice is the original definition of tan(x)
So using this definition of tan(x) we can use the givens sin(x) and cos(x) to find tan(x)

plugging in sin(x) and cos(x) we get:

We usually don't like square roots in the denominator, and from here we want to rationalize the denominator which we do by removing the square root from the denominator.
We can do this by multiplying the fraction by:
which doesn't change the value of the fraction since it simplifies to 1, but it gets rid of the square root in the denominator
