Question

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Answer 1

Answer:

x = $\frac{5}{4} + \frac{ \sqrt{5} }{4}$

x = $\frac{5}{4} - \frac{ \sqrt{5} }{4}$

Step-by-step explanation:

Quadratic equation:

$x = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}$

The equation is:

$4x^2 - 10x + 5 = 0$

So:

a = 4

b = -10

c = 5

Plug the variables into the quadratic equation:

$x = \frac{-(-10) +- \sqrt{(-10)^2 - (4 * 4 * 5)} }{(2 * 4)}$

$x = \frac{\sqrt{10 +- \sqrt{100 - 80} } }{8}$

$x = \frac{10 + \sqrt{20} }{8}$

Divide both sides by 8:

10 ÷ 8 = $\frac{5}{4}$

$\sqrt{20}$ ÷ 8 = $\frac{\sqrt{5}}{4}$

$\frac{5}{4}$ +- $\frac{\sqrt{5}}{4}$

This means that the solutions that satisfy the equation is:

x = $\frac{5}{4} + \frac{ \sqrt{5} }{4}$

x = $\frac{5}{4} - \frac{ \sqrt{5} }{4}$

Hope this helps!

Answer 2

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