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lyudmila [28]
2 years ago
12

Let

Mathematics
1 answer:
kramer2 years ago
3 0

I think when you copied and pasted your question it re arranged itself

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PLEASE HELP IM BEING TIMED
Zigmanuir [339]

Step-by-step explanation:

You have miscopied the second equation as it contains a third variable B when there isn't a B in the answers.

Please correct it for assistance

7 0
3 years ago
What's the distributive property for 16+48
ella [17]
The distributive property is when you have, for example, 2(1+3), and you multiply the 2 by both terms and add them together. so 2(1+3) = 2(1) + 2(3) = 2 + 6 = 8.

so with 16 + 48, to show the distributive property, you could divide by any common factor of 16 and 48. some correct ways to do this are:

16 + 48 = 2(8 + 24)
16 + 48 = 4(4 + 12)
16 + 48 = 8(2 + 6)
16 + 48 = 16(1 + 3)

you're just dividing 16 and 48 by the outside term to get the 2 numbers in the ( )
6 0
3 years ago
Read 2 more answers
Help guys with the question
Naya [18.7K]

Answer:

\sin\Big(\dfrac{\theta }{2}\Big) = \dfrac{2\sqrt 5}{5}

Step-by-step explanation:

\cos(2x) = \cos^2 x-\sin^2 x = 1-2\sin^2 x \\ \\ \cos(x) = 1-2\sin^2 (\frac{x}{2}) \\ \\ \Rightarrow \sin^2 (\frac{x}{2}) = \dfrac{1-\cos(x)}{2}\\ \\ \sin(\frac{x}{2}) = \pm \sqrt{\dfrac{1-\cos(x)}{2}},\quad x\in [\frac{3\pi }{2},\pi] \Rightarrow \frac{x}{2}\in [\frac{3\pi}{4},\frac{\pi}{2}]\\ \\ \Rightarrow \sin(\frac{x}{2}) > 0 \Rightarrow \sin(\frac{x}{2}) = \sqrt{\dfrac{1-(-\frac{3}{5})}{2}} \Rightarrow \sin(\frac{x}{2}) = \sqrt{\dfrac{8}{10}}=\dfrac{2\sqrt 2}{\sqrt{10}} = \\ \\ =\dfrac{2\sqrt 5}{5}

7 0
3 years ago
Find 4 consecutive even integers such that the sum of the first and three times the fourth is equal to 48 more than the sum of 2
serious [3.7K]

Answer:

18 , 20 , 22 and 24.

Step-by-step explanation:

Let the numbers be n , n + 2, n + 4 and n + 6.

So we have the following equation:

n + 3(n + 6) =  48 + n + 2 + n + 4

n + 3n + 18 = 48 + 2n + 6

4n + 18 = 2n + 54

2n = 36

n = 18

So the numbers are 18 , 20 , 22 and 24.

3 0
3 years ago
Triangle A'B'C' is the result of dilating ABC about point P by a scale factor of 2.
beks73 [17]

Answer:

Step-by-step explanation:

use formula

(x,y)=(kx,ky)   (k means scale factor)

A(1,1)=A'(1*2,1*2+

A'=(2,2)

B(3,1)=B'(3*2,1*2)

B'=(6,2)

C(3,-3)=C'(3*2,-3*2)

C'=(6,-6)

8 0
3 years ago
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