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sergiy2304 [10]
2 years ago
10

Find the point of intersection between the lines: y=3x-1 and y-x+3=0

Mathematics
1 answer:
Anon25 [30]2 years ago
8 0

Answer:

<em>( - 1 , - 4 ) </em>

Step-by-step explanation:

y = 3x - 1

y = x - 3

3x - 1 = x - 3 ⇒ <u><em>x = - 1</em></u>

y = 3( - 1 ) - 1 = - 4

<u><em>y = -  4</em></u>

<em>( - 1 , - 4 )</em>

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<h3>Answer:   (x-2)(x+2)(x+3)(x+3)</h3>

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===============================================

Explanation:

x^2-4 factors to (x-2)(x+2) after using the difference of squares rule

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So overall, the original expression factors to (x-2)(x+2)(x+3)(x+3)

We can condense this into (x-2)(x+2)(x+3)^2 since (x+3)(x+3) is the same as (x+3)^2

-------------------

Side notes:

  • Difference of squares rule is a^2 - b^2 = (a-b)(a+b)
  • The perfect square trinomial factoring rule is a^2+2ab+b^2 = (a+b)^2
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