2 years ago

Find the point of intersection between the lines: y=3x-1 and y-x+3=0

Mathematics

1 answer:

Anon25 [30]2 years ago

8 0

Answer:

( - 1 , - 4 )

Step-by-step explanation:

y = 3x - 1

y = x - 3

3x - 1 = x - 3 ⇒ x = - 1

y = 3( - 1 ) - 1 = - 4

y = - 4

( - 1 , - 4 )

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F the graph of y=ax+b/x+c has a horizontal asymptote y=2 and a vertical asymptote x=-3 then a+c=?

Pachacha [2.7K]

Correct answer is E.

$y= \frac{ax+b}{x+c}
\\
\\ \lim_{x \to \infty} \frac{ax+b}{x+c}=2
\\
\\ \lim_{x \to \infty} \frac{ \frac{ax}{x} + \frac{b}{x} }{ \frac{x}{x} + \frac{c}{x} }=2
\\
\\ \lim_{x \to \infty} \frac{a + \frac{b}{x} }{ 1 + \frac{c}{x} }=2
\\ \frac{a + 0}{ 1 + 0 }=2
\\
\\ \frac{a}{1} =2
\\a=2
\\
\\x+c=0
\\-3+c=0
\\c=3
\\
\\a+c=2+3=5


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