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2 years ago

Find the point of intersection between the lines: y=3x-1 and y-x+3=0

Mathematics

1 answer:

Anon25 [30]2 years ago

8 0

Answer:

( - 1 , - 4 )

Step-by-step explanation:

y = 3x - 1

y = x - 3

3x - 1 = x - 3 ⇒ x = - 1

y = 3( - 1 ) - 1 = - 4

y = - 4

( - 1 , - 4 )

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Given the equations x + y = 20 and x - y = 8, which values of x and y

hammer [34]

Answer:

x = 14 and y = 6

Step-by-step explanation:

To find the solution to this problem, we plug in the values of x and y from each answer choice and simplify.

(11) + (9) = 20. 20 = 20.
(11) - (9) = 20. 2 ≠ 8.

(9) + (11) = 20. 20 = 20
(9) - (11) = 20. -2 ≠ 8.

(14) + (6) = 20. 20 = 20.
(14) - (6) = 8. 8 = 8.

(6) + (14) = 20. 20 = 20
(6) - (14) = 8. -8 ≠ 8.

Therefore, the correct answer is x = 14 and y = 6.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

6 0

2 years ago

What is the area of a rectangles with the side lengths 5 inches and 4/3 inches?

adell [148]

Answer: 20/3 square inches

Step-by-step explanation:

Area = length*width

length = 5 in.

width = 4/3 in.

A = 5 * (4/3) = 20/3 in^2

7 0

3 years ago

Write the phrase as an expression. Then simplify the expression. The product of 8 and a number y multiplied by 9

Neporo4naja [7]

Answer:

8y x 9 ⇒ 72y

Step-by-step explanation:

5 0

4 years ago

What is the following product? (4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago

Get brainiest !! Easyyy question

Reika [66]

Answer:

Step-by-step explanation:

hmmm

7 0

3 years ago

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