No, they're not equivalent....... i suggest a calculator for this kind of math, just divide the first number by the last and compare them, like this 36/4=9, 56/7=8
the first one is $9 per hat, and the second one is $8 per hat
Answer:
3xyzsquare root of xy^2
the third option
Step-by-step explanation:
look for what you cn take from all of it equally
Here is a list of the odd number paired
1+3, 1+5, !+7, and !+9 (there are 4 unique sums - 4, 6,8 and 10)
3+5, 3+7, 3+9 (notice I did not pair 3 with 1 and the the only new sum is 12)
5+7, 5+9 (the only new sum is 14)
7+9 (16 is a new sum)
The sums (no repeats) are 4,6,8,10,12,14 and 16 for a total of seven numbers.
Area = 2,520m^2
(47+65)/2 = 56
56x45 = 2,520
2x + 6 < x + 20
- x - x
x + 6 < 20
- 6 - 6
x < 14
Solution Set: (-∞, 14)