12. Find three consecutive even integers such that
1 answer:
Answer:
10, 11, 12
Step-by-step explanation:
Hi there!
Let <em>x</em> be equal to the smallest integer.
Let <em>x</em>+1 and <em>x</em>+2 be equal to the consecutive integers.
We're given that:
⇒ smallest integer + 2 × middle integer = 20 + largest integer
Construct an equation:

Combine like terms:

Therefore, the smallest integer is 10.
This makes the consecutive integers 11 and 12.
I hope this helps!
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Step-by-step explanation:
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