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Marizza181 [45]
3 years ago
8

Factoring-16w²+50wz-21z²  please help me solve

Mathematics
1 answer:
KIM [24]3 years ago
6 0
-16w^2+50wz-21z^2=-(16w^2-50wz+21z^2)=\\\\=-(16w^2-8wz-42wz-21z^2)=\\\\-[8w(2w-z)-21z(2w-z)]=-(2w-z)(8w-21z)
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Which of the following is not necessarily true for independent events A and B? P (A intersection B )equals P (A )P (B )P (A vert
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Answer:

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Step-by-step explanation:

Reading the options that we have for the answer, one of them (the first one) is the definition of being independent. A and B are independent if and only if P(A ∩ B)=P(A)*P(B).

So the first one IS necessary true for independent events and with this equation, option two and three are necessary true for independent events:

For definition of P(A | B)

P(A | B)= P(A ∩ B) / P(B)

And we replace P(A ∩ B) using the first option that we know it´s true:

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So P(A | B)=P(A) it´s true for A and B independent.

The same process goes to show P(B | A)=P(B)

Because of this, the only one of the options that could not be true for independent events is P(A ∪ B)=P(A) + P(B), and this happens because P(A ∩ B)=P(A)*P(B) applies but it could be different from 0 considering P(A ∪ B)=P(A) + P(B) - P(A ∩ B). We conclude this property (P(A ∪ B)=P(A) + P(B)) is not necessary true for A and B independent.

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3 years ago
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to find a common denominator, you have to find the number which both numbers equally go into! so no decimals. check the times tables!

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