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3 years ago

Factoring-16w²+50wz-21z² please help me solve

Mathematics

1 answer:

KIM [24]3 years ago

6 0

$-16w^2+50wz-21z^2=-(16w^2-50wz+21z^2)=\\\\=-(16w^2-8wz-42wz-21z^2)=\\\\-[8w(2w-z)-21z(2w-z)]=-(2w-z)(8w-21z)$

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oee [108]

The area enclosed by the figure is 4533.48 square meters.

<u>Step-by-step explanation:</u>

Side length of the square = 42m

The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.

Radius of the semicircle = 21m

Area of the square = 42 x 42 = 1764 square meters

Area of 1 semicircle = π(21 x 21) /2

= (3.14) (441) /2

= 1384.74/2

= 692.37 square meters

Area of 4 semicircle = 4 x 692.37

= 2769.48 square meters

Total area = 1764 + 2769.48

= 4533.48 square meters

The area enclosed by the figure is 4533.48 square meters.

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3 years ago

Malcolm is filling bags with rice. He starts with a 5 1/4 pound container of rice and fills each

Sliva [168]

Basically we want to know how many times 5/8 goes into 5 1/4.

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Since we cannot have a fraction of a bag, he can fill 8 bags completely.

answer: 8 bags

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3 years ago

The prichard family drinks 2 quarts of milk per day.How many gallons of milk do they drink in a week?

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The Prichard family drinks 3.5 gallons in a week.

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3 years ago

Find the nth term of<br>1x2x3+2x5x6+3 x 4x

vlada-n [284]

Answer:

66+12x

Step-by-step explanation:

1x2x3+2x5x6+3x4x

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3 years ago

if the diameter of the front wheels on the locomotive is 4 ft what is the diameter of the front wheels on the model. Express the

Leto [7]

Question is Incomplete, Complete question is given below.

Consider a model of a train locomotive that has a similarity transformation map of x arrow right 48x from the model to the actual locomotive when answering the question.

If the diameter of the front wheels on the locomotive is 4 feet, what is the diameter of the front wheels on the model? Express the answer in inches.

Answer:

The diameter of front wheel on the model is 1 inch.

Step-by-step explanation:

Given:

Let diameter of the front wheel on the model be 'x'.

Actual diameter of front wheel = 4 feet

Now given that ratio model to actual = $\frac{x}{48x}= \frac{1}{48}$

Now we can say that ratio model to actual is equal to ratio of model diameter of front wheel to actual diameter of front wheel.

framing in equation form we get;

$\frac{x}{4}=\frac{1}{48}\\\\x=\frac{4}{48} = \frac{1}{12} \ ft.$

Now we know that;

$\frac{1}{12}\ ft = 1 \ in.$

Hence The diameter of front wheel on the model is 1 inch.

6 0

3 years ago