I believe the answer is d
Answer:
81.86%
Step-by-step explanation:
We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.
First of all we will find z-score using z-score formula.
Now let us find z-score for 86.
Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.
Using normal distribution table we will get,

We will use formula
to find the probability to find that a normal variable lies between two values.
Upon substituting our given values in above formula we will get,


Upon converting 0.81859 to percentage we will get

Therefore, 81.86% of final exam score will be between 68 and 86.
Move 50x to the opposite sude so 50x-200>-75
move 200 over so 50x> 125
divide so x>2.5
Answer:
60
Step-by-step explanation:
Answer: x=15
Step-by-step explanation:Step 1: Cross-multiply.
5
4
=
x
12
(5)*(12)=x*(4)
60=4x
Step 2: Flip the equation.
4x=60
Step 3: Divide both sides by 4.
4x
4
=
60
4
x=15
Answer:
x=15