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DaniilM [7]
2 years ago
7

Tiffany is filling her daughter's pool with water from a hose. She can fill the pool at a rate of 1/10 gallons per second.

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
8 0
At first I assumed you were asking for 3 different ratios equivalent to 1/10, which could be 2/20, 10/100, or 5/50. But it seems you are asking for ratios equivalent to 1/10 gallons to second. For this, you could change both the 'gallons' and the 'seconds' to get different unit with the same ratio. 1/10 gallon / second * 60 seconds / 1 minute gallons / minute 1/10 gallon / second * 1 gallon / 4 quarts = 1/40 quarts / second combining these two conversions we can do 1/10 gallon / second * 60 second / 1 minute * 1 gallon / 4 quarts = 3/2% 3D

Final answer: 1/10 gallons / second = 6 gallons / minute = 1/40% 3D quarts / second = 3/2 quarts / minute Hope I helped :)
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Write an equation of each line in point-slope form. containing (2,1) and (3,4)
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Answer:

y=3x-5

Step-by-step explanation:

This is the only line that will pass through these points.

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A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test.
PtichkaEL [24]
Answer: The answer is A

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7 0
3 years ago
Please help! I don't really understand this.
ch4aika [34]

Step-by-step explanation:

11.

Area of rectangle = 408 in²

Length = 3x-2 and width = x

The area of a rectangle is given by :

A = lb

(3x-2)x = 408

x = 12 inch and x = -11.33 in

Neglecting negative value,

The width of rectangle = 12 inch

The length of rectangle = 3x-2 = 3(12)-2 = 34 inch

12.

Base of triangle = 2x+2

Height = x

The area of a triangle is given by :

A=\dfrac{1}{2}bh\\\\600=\dfrac{1}{2}\times (2x+2)x\\\\600=(x+1)x

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8 0
3 years ago
(7)(8)(9)<br><br> Geometry<br><br> Check Ans<br><br> 7) s = 15<br> 8) y = 64 x = 99<br> 9) 96
Katyanochek1 [597]
Problem 7: Correct
Problem 8: Correct
Problem 9: Correct

The steps are below if you are curious

===========================================================================================

Problem 7

S = 180*(n-2)
2340 = 180*(n-2)
2340/180 = n-2
13 = n-2
n-2 = 13
n = 13+2
n = 15

I'm using n in place of lowercase s, but the idea is the same. If anything, it is better to use n for the number of sides since S already stands for the sum of the interior angles. I'm not sure why your teacher decided to swap things like that.

===========================================================================================

Problem 8

First find y
y+116 = 180
y+116-116 = 180-116
y = 64

which is then used to find x. The quadrilateral angles add up to 180*(n-2) = 180*(4-2) = 360 degrees
Add up the 4 angles, set the sum equal to 360, solve for x

x+y+125+72 = 360
x+64+125+72 = 360 ... substitution (plug in y = 64)
x+261 = 360
x+261-261 = 360-261
x = 99

===========================================================================================

Problem 9

With any polygon, the sum of the exterior angles is always 360 degrees

The first two exterior angles add to 264. The missing exterior angle is x
x+264 = 360
x+264-264 = 360-264
x = 96

6 0
3 years ago
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