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DaniilM [7]
2 years ago
7

Tiffany is filling her daughter's pool with water from a hose. She can fill the pool at a rate of 1/10 gallons per second.

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
8 0
At first I assumed you were asking for 3 different ratios equivalent to 1/10, which could be 2/20, 10/100, or 5/50. But it seems you are asking for ratios equivalent to 1/10 gallons to second. For this, you could change both the 'gallons' and the 'seconds' to get different unit with the same ratio. 1/10 gallon / second * 60 seconds / 1 minute gallons / minute 1/10 gallon / second * 1 gallon / 4 quarts = 1/40 quarts / second combining these two conversions we can do 1/10 gallon / second * 60 second / 1 minute * 1 gallon / 4 quarts = 3/2% 3D

Final answer: 1/10 gallons / second = 6 gallons / minute = 1/40% 3D quarts / second = 3/2 quarts / minute Hope I helped :)
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the perimeter of a rectangle is 60 meters. if the length of the rectangle is 14 meters. what is the width of the rectangle.,
Ray Of Light [21]
Perimeter is 2width+2length
Therefore since you already know that the perimeter is 60 and the length is 14 you can set up the equation; 
60= 2w+14
with this you then need to find w so;
60=2w+14
-14     -14
46=2w
(46/2)=(2w/2)
13=w
The width is 13
8 0
3 years ago
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What is the answer? Reduce 981/387
Sergeu [11.5K]
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7 0
4 years ago
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Evaluate 6 - 2(-1) +1-51 =<br> 09<br> 01<br> 13
Elenna [48]
Answer might be 9 due to my algebra teacher
7 0
3 years ago
How would you solve these 2 maths problems?
sweet-ann [11.9K]

Answer:

see explanation

Step-by-step explanation:

(9)

Expand and simplify right side and compare coefficients of like terms on left side.

(x - 2)(x² + ax + b) + c

= x³ + ax² + bx - 2x² - 2ax - 2b + c

= x³ + x²(a - 2) + x(b - 2a) - 2b + c

compare with

x³ + 2x² - 3x + 4

x² terms

a - 2 = 2 ( add 2 to both sides )

a = 4

x terms

b - 2a = - 3 ← substitute a = 4

b - 8 = - 3 ( add 8 to both sides )

b = 5

constant terms

- 2b + c = 4 ← substitute b = 5

- 10 + c = 4 ( add 10 to both sides )

c = 14

Thus a = 4, b = 5 and c = 14

-------------------------------------------------

(10)

Since both functions cross the x- axis at - 2 then (- 2, 0) satisfies both, that is

f(- 2) = (-2)^{4} + a(- 2)³ + b(- 2)² + 36(- 2) + 144 = 0, that is

- 16 - 8a + 4b - 72 + 144 = 0

- 8a + 4b + 56 = 0

- 8a + 4b = - 56 → (1)

and

g(- 2) = (-2)^{4} + (a + 3)(- 2)³ - 23(- 2)² + (b + 10)(- 2) + 40 = 0, that is

- 16 - 8(a + 3) - 92 - 2(b + 10) + 40 = 0

- 16 - 8a - 24 - 92 - 2b - 20 + 40 = 0

- 8a - 2b - 112 = 0

- 8a - 2b = 112 → (2)

Subtract (1) from (2) term by term

- 6b = 168 ( divide both sides by - 6 )

b = - 28

Substitute b = - 28 into (2)

- 8a + 56 = 112 ( subtract 56 from both sides )

- 8a = 56 ( divide both sides by - 8 )

a = - 7

Thus a = - 7 and b = - 28

5 0
3 years ago
[2+(6times8)]-1 plz help
bezimeni [28]

[2+(6times8)]-1

= [2+(6 * 8)] -1

= [2+(48)] -1

= 50  -1

= 49

8 0
3 years ago
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