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DerKrebs [107]
3 years ago
10

Simplify. 8.8a - 2.9a

Mathematics
2 answers:
marshall27 [118]3 years ago
7 0
Its the same sign so simply:

8.8 minus 2.9

Which is 5.9

The answer is 5.9a
crimeas [40]3 years ago
6 0
5.9a
Hope this helps
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The red blood cell counts​ (in millions of cells per​ microliter) for a population of adult males can be approximated by a norma
skad [1K]

Answer:

(a) Minimum red blood cells 5.744 million cells per micro liter

(b) Maximum red blood cells 5.068 million cells per micro liter.

Step-by-step explanation:

Z-score formula is = \frac{x-u}{Standard deviation}

Z-score = \frac{x-5.5}{0.4}

The value of z-score is 0.61 so then x will be;

x = 5.744

The minimum red blood cells count that can in top is 27% of count which is 5.744 million cells per micro liter.

Z-score = \frac{x-5.5}{0.4}

The value of z-score is 0.14 so then x will be;

x = 5.068

The maximum red blood cells count that can be in top is 14% of count which is 5.068 million cells per micro liter.

6 0
3 years ago
A circle has a circumference of 907.46907.46 units. What is the diameter of the circle?
astra-53 [7]

question is wrong sir

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6 0
3 years ago
What is the length of Arc AB, if the radius of Circle L is 12 inches?
grigory [225]
Hello : 
<span>The circumference of the circle is 24π inches 
</span>
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6 0
3 years ago
Corey spent 18 minutes coloring. She spent 6 times as many minutes reading
ruslelena [56]

Answer:

18 x 6 =108. she spent 108 minutes reading.

Step-by-step explanation:

3 0
2 years ago
A researcher wishes to estimate the number of households with two cars. How large a sample is needed in order to be 99% confiden
solmaris [256]

Answer:

Sample size n = 1382

so correct option is D) 1382

Step-by-step explanation:

given data

confidence level = 99 %

margin of error = 3%

probability = 25 %

to find out

How large a sample size needed

solution

we know here P = 25 %

so 1 - P = 1 - 0.25

1 - P  = 0.75

and we know E margin of error is 0.03 so value of Z for 99%

α = 1 - 99%   = 1 - 0.99

α  = 0.01

and  \frac{\alpha}{2} = \frac{0.01}{2}

\frac{\alpha}{2}  = 0.005

so Z is here

Z_(\frac{\alpha}{2}) = 2.576

so

sample size will be

Sample size n =  (\frac{(Z_(\frac{\alpha}{2})}{E})^2 * P * (1-P)

put here value

Sample size n = (\frac{2.576}{0.03})^2 * 0.25 * 0.75

Sample size n = 1382

so correct option is D) 1382

3 0
3 years ago
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