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3 years ago

F(x) = x^2. What is g(x)?

Mathematics

1 answer:

fredd [130]3 years ago

3 0

Good evening ,

Answer:

B. g(x)= -x² - 4

___________________

Step-by-step explanation:

The graph of g is downward facing then we must have (-) before the x²

Since, The vertex of parabola g is on point (0 ,-4) then we have to subtract 4.

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Afina-wow [57]

Answer:

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Step-by-step explanation:

See the image for a Venn diagram illustrating relationships among the various subsets of real numbers.

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3 years ago

ABCD is a quadrilateral. Sides are extended as shown. Show that x = 100°

geniusboy [140]

Solution :

Given :

ABCD is a quadrilateral.

Angle ADC = 90 degree

Angle DCB = 120 degree

Now angle DAB = 70 degree (alternate angles)

We know that the interior angles of a quadrilateral is 360 degrees.

So,

∠ DAB + ∠ ABC + ∠ BCD + ∠ CDA = 360°

70° + ∠ ABC + 120° + 90 ° = 360°

∠ ABC = 360° - (70° + 120° + 90°)

∠ ABC = 360° - 280°

∠ ABC = 80°

Now ∠ x = 180° - ∠ ABC (Line AB extended is 180° )

= 180° - 80°

= 100°

Hence proved.

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3 years ago

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devlian [24]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

The product of X and 7 equals 28

ki77a [65]

When you are looking for this, the best way to do this is to divide 28 by 7. This will give you 4.
The other way to do this is to list the factors of 28, which are 1,2,4,7,14,28, and you will then be able to see which two are paired.
In this case, x is 4.
Hope I have been able to help you

4 0

3 years ago

Determine whether or not F is a conservative vector field. If it is, find a function f such that F = ∇f. (If the vector field is

Elis [28]

In order for F to be conservative, there must be a scalar function f such that the gradient of f is equal to F. This means

$\dfrac{\partial f}{\partial x}=3x^2-2y^2$

$\dfrac{\partial f}{\partial y}=4xy+4$

Integrate both sides of the first equation with respect to x :

$f(x,y)=x^3-2xy^2+g(y)$

Differentiate both sides with respect to y :

$\dfrac{\partial f}{\partial y}=-4xy+\dfrac{\mathrm dg}{\mathrm dy}=4xy+4\implies\dfrac{\mathrm dg}{\mathrm dy}=8xy+4$

But we assume g is a function of y, which means its derivative can't possibly contain x, so there is no scalar function f whose gradient is F. Therefore F is not conservative.

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3 years ago