Answer:
Im pretty sure its 11.6
Step-by-step explanation:
Answer:
Check attachment
Step-by-step explanation:
Check attachment
Answer:
S= z (y-x)/(x+y)
Step-by-step explanation:
Lets the speed of high speed train = u
Lets the regular speed train = v
We know that
Distance = Speed x time
For high speed train
z = u .x
u= z/x ----------1
For regular speed train
z = v .y
v = z/y -------------2
Both are traveling in opposite direction so relative speed
Vr = z / x+ z /y
Lets in time t they will meet
z = (z / x+ z /y) t
t= xy/ (x+y)
Lets take distance cover by high speed train is m when it moves A to B and speed cover by regular train is n when it is moving B to A.They meet at time t.
m = u .t
m = z / x .xy/ (x+y)
m = zy/ (x+y) -----------3
n = v .t
n = z / y .xy/ (x+y)
n = zx/ (x+y) -----------4
From equation 3 and 4
So
m - n= zy/ (x+y) - zx/ (x+y)
S= z (y-x)/(x+y)
Option a is correct.
Answer:
d) 260m^3
Step-by-step explanation:
length x width x height
13*10*2 = 260m³
Answer:
the answer should be 44 dollar correct me if im wrong
Step-by-step explanation:
