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Yuki888 [10]
3 years ago
14

Factor 3x^3+3x^2+x+1

Mathematics
2 answers:
Nat2105 [25]3 years ago
6 0
We can solve it like:
3x^3+3x^2+x+1= (3x^3+3x^2)+(x+1)=
3x^2(x+1)+(x+1)=
= (x+1)(3x^2+1)

Have a good day
bixtya [17]3 years ago
5 0
(3x³ + 3x²) + (x + 1)
3x²(x + 1) + 1(x + 1)
(3x² + 1)(x + 1)

Factored form: (3x² + 1)(x + 1)


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Step-by-step explanation:

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andrezito [222]

Answer:

1. x = ±9

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Step-by-step explanation:

According to the questions,

Problem 1. x^{2}-81=0 i.e. x^{2}=81 i.e. x = ±9.

Problem 2. 2x^{2}-26=0 i.e. x^{2}-13=0 i.e. x^{2}=13 i.e. x=\pm \sqrt{13}

Problem 3. [tex]f(x)=x^{2}-144[tex]

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Problem 4. We have [tex]f(x)=x^{2}+25[tex]

For the roots, we take, [tex]x^{2}+25=0[tex] i.e. [tex]x^{2}=25[tex] i.e. x = ±5.

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