P=63+63(3/100)
p=63(1+3/100)
p=63(1.03)
p=$64.89
we are given with two dice and that we are asked in the problem to find the probability of the following:
a. sum at least 4b. sum at least 6
THe sample space of this problem is
{11, 12, 13, 14, 15, 16, 21,22, 23,24,25,26,31,32,33,34,35,36,41,42,43,44,45,46,51,52,53,54,55,56,61,62,63,64,65,66} a total of 36.a. 33/36 = 11/12b.11/36
x = (180 - 55) + (180 - 25) = 280°
Answer: x = 280°
Answer:
b is the answer
Step-by-step explanation:
64*.2 =12.8
64-12.8= 51.2
51.2*.06= 3.072
3.07+51.2=54.27
answer is $54.27