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zhuklara [117]
3 years ago
7

(x2 - 10x + 25) + (y2 - 16y +64) = 16 center (, ) radius =

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
4 0
The standard equation for a circle is 

(x-h)^2 + (y-k)^2 = r^2

where the center is at point (h,k) and r is the radius.

To investigate this, check first if the quadratic equations are a perfect square. This is determined by dividing the middle term by 2 and taking its square. If it equals to the third term, it is a perfect square.

For (x^2 - 10x +25): (-10/2)^2 = 25 (perfect square)
For (y^2 - 16y + 64): (-16/2)^2 = 64 (perfect square)

Then, we simplify the equation by factoring:

(x - 5)^2 + (y -- 8)^2 = 16

Thus, the center is at point (5,8)
Also, the radius is square root of 16, which is 4.


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Which of these lines is perpendicular to the line y = 3x + 2?
Morgarella [4.7K]

Answer:

(c)  y=\frac{-1}{3}x+4  will be perpendicular to the line y = 3x+2

Step-by-step explanation:

We have given the the equation of line as y = 3x+2

We know the equation of line as y = mx+c , here m is slope and c is intercept

On comparing with standard equation of line m = 3

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Now (a) Line is given as y=\frac{1}{3}x+3 its slope is \frac{1}{3} so it will be not perpendicular

(b)  Line is given as y=\frac{1}{3}x+2 its slope is \frac{1}{3} so it will be not perpendicular

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(d) Line is given as y=3x+\frac{1}{2} its slope is 3 so it will not perpendicular to the line y = 3x+2

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Step-by-step explanation:

3 0
3 years ago
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Mademuasel [1]
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