Answer:
Charlie is incoerre
Step-by-step explanation:
Given that :
Line of sight to top of flagpole = 16 feets
Angle of elevation = 60°
The height of the flagpole :
Applying trigonometry to the drawing in the attached picture :
We use:
Sinα = opposite / hypotenus
This enables us to use the value of the hypotenus (line of sight) to obtain the missing height value (h)
Sin(60°) = h / 16
h = 16 * sin 60
h = 16 * 0.8660254
h = 13.856406
Hence flagpole is about 13.86 feets high
Charlie's reasoning is incorrect, the line of sight constitutes the hypotenus and not Adjacent and hence, shoul
47 -14i
You can work this out in the straight-forward way, or you can recognize that (6-i) is a common factor. In the latter case, you have ...
... = (6-i)(5 + 3-i)
... = (6 -i)(8 -i)
This product of binomials is found in the usual way. Each term of one factor is multiplied by each term of the other factor and the results summed. Of course, i = √-1, so i² = -1.
... = 6·8 -6i -8i +i²
... = 48 -14i -1
... =
_____
A suitable graphing calculator will work these complex number problems easily.
Answer:
648 cubic centimeters
Step-by-step explanation:
6×9×12=648
Answer:
% area of the shaded region = 33%
Step-by-step explanation:
Radius of the middle circle = 7 cm
Radius of the inner circle = 4 cm
Area of the middle circle = πr²
= π(7)²
= 49π
Area of the inner circle = π(4)²
= 16π
Area of the shaded region= 49π - 16π
= 33π
Area of the outermost circle = π(10)²
= 100π
% area of the shaded region =
=
= 33%
Therefore, area of the shaded region is 33% of the complete logo.