Answer:
Can't answer because we don't know the distance between start position and Middelburg, as well as the number of stops along the way
Step-by-step explanation:
Answer:
The value of x is 4
Step-by-step explanation:
In a right triangle, if a segment is drawn from the right angle ⊥ to the hypotenuse like the given figure, then
∵ The length of one side of the right triangle = (x + 2)
∵ The length of the hypotenuse = x + 5
∴ (x + 2)² = x (x + 5)
∵ (x + 2)² = (x + 2)(x + 2)
∴ (x + 2)(x + 2) = x(x + 5)
→ Simplify the two sides
∵ (x)(x) + (x)(2) + (2)(x) + (2)(2) = (x)(x) + (x)(5)
∴ x² + 2x + 2x + 4 = x² + 5x
→ Add the like terms in the left side
∴ x² + 4x + 4 = x² + 5x
→ Subtract x² from both sides
∵ x² - x² + 4x + 4 = x² - x² + 5x
∴ 4x + 4 = 5x
→ Subtract 4x from both sides
∴ 4x - 4x + 4 = 5x - 4x
∴ 4 = x
∴ The value of x is 4
Answer:
Right
Step-by-step explanation:
For a contrapositive, we switch the hypothesis and conclusion and then negate it.
Switch
If it is a tree, then it is an elm
Negate
If it is not a tree, then it is not an elm.
Not tree belongs inside not elm
Right
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
10 times 'x' is 10 times whatever the value of 'x' is. I hope that makes sense.
